· G - Smaller Sum · CF2009G2 Yunli's Subarray Queries (hard version) · CF2009G. Yunli's Subarray Queries 题解 · Codeforces Round 971 (Div. 4) 阅读排行: · 开发的设计和重构,为开发效率服务 · 从零开始开发一个 MCP Server! · Ai满嘴顺口溜,想考研?浪费我几个小时 · 从问...
问到区间异或和首先想到前缀和,定义sum[ i ] 为1 ~ i 的异或值 对于每个r,查找有多少sum[ i ] & sum[ r ] >=k,首先想到01字典树,从高位像低位贪心。如果该位有异或值大于K的情况,如x=1,k=0,那么先加上cnt[son [ p1 ] ](因为该位已经大于了,后面不用再讨论了),然后让p = son[ p0] (让...
求出前缀和,问题变成了O(n*n)复杂度的问题,但是仍然不能解决问题。 设prefix为前缀和,设i < j,一般都是通过算sum = prefix[j] - prefix[i]求和的最大值,但是本题中有取模,要求sum最大。 第一种情况:如果prefix[j] > prefix[i],sum < prefix[j],这种情况就不需要考虑了。 第二种情况:prefix[j]...
You need to find the number of subarrays in A having sum less than B. We may assume that there is no overflow. Problem Constraints 1 <= N <= 10000, -100<=A[i]<=100, 0<=B<=10000 Example: INPUT:: A---> [1,−2,4,8], B=0, OUTPUT: 2...
Maximum Sum Queries wisdompeak 165 0 32:27 【LeetCode】2097. Valid Arrangement of Pairs wisdompeak 91 1 17:46 【LeetCode】1964. Find the Longest Valid Obstacle Course at Each Position wisdompeak 115 0 08:41 【LeetCode】357. Count Numbers with Unique Digits wisdompeak 93 0 12:29...
Given an array of integers A, find the sum of min(B), where B ranges over every (contiguous) subarray of A. Since the answer may be large, return the answer modulo 10^9 + 7. Example 1: Input: [3,1,2,4...leetcode: Maximum Length of Repeated Subarray Question Given two integer...
918. Maximum Sum Circular Subarray # 题目# Given a circular array C of integers represented by A, find the maximum possible sum of a non-empty subarray of C. Here, a circular array means the end of the array connects to the beginning of the array. (Formally, C[i] = A[i] when 0...
The first line contains one integer tt (1≤t≤3⋅1051≤t≤3⋅105) — the number of queries. The first line of each query contains one integer nn (1≤n≤3⋅1051≤n≤3⋅105). The second line of each query contains nn integers a1,a2,…,ana1,a2,…,an (1≤ai≤n1≤ai≤n)...
Input There are several tests, process till the end of input. For each test, the first line consists of two integers N and Q, denoting the length of the array and the number of queries, respectively. N positive integers are listed in the second line, followed by Q lines each containing...
push_back(i); } std::vector jump(logN + 1, std::vector<int>(n + 1, -1)); std::vector sum(logN + 1, std::vector(n + 1)); jump[0] = R; for (int i = 1; i <= n; i++) { if (jump[0][i] != -1) { sum[0][i] = i64(jump[0][i] - i) * f[i]; } ...