struct ListNode* ReverseList(struct ListNode* head ) { // write code here struct ListNode* newnode = NULL; if((head == NULL) || (head->next == NULL)) return head; else { newnode = ReverseList(head->next); head->next->next = head; head->next = NULL; return newnode; } }点...
struct ListNode* ReverseList(struct ListNode* head ) { // write code here if(head == NULL) { return head; } struct ListNode *p = head->next; head->next = NULL; if(p == NULL) { return head; } struct ListNode* t = ReverseList(p); p->next = head; return t; }点...
struct ListNode { int val; ListNode *next; ListNode(int x) : val(x), next(NULL) {} }; class Solution { public: bool hasCycle(ListNode *head) { if(head == NULL) return false; ListNode* walker = head; ListNode* runner = head; while(runner->next != NULL && walker->next != NULL...
struct ListNode *reverseList(struct ListNode *head) { if(head == NULL) { returnNULL; } if(head->next == NULL) { returnhead; } struct ListNode *reversedHead = NULL; struct ListNode *prevNode = NULL; struct ListNode *currentNode = head; while(currentNode != NULL) { struct ListNode *...
代码语言:txt 复制 void printList(struct ListNode* head) { struct ListNode* current = head; while (current != NULL) { printf("%s ", current->str); current = current->next; } } void updateNode(struct ListNode* node, char* newStr) { strcpy(node->str, newStr); } ...
(struct ListNode* head, int m, int n ) { // write code here struct ListNode*prev=NULL; struct ListNode*next=NULL; struct ListNode*phead=head; struct ListNode*reverseBegin=NULL; struct ListNode*reverseEnd=NULL;//define struct,define as NULL int i=1; if(NULL==head||NULL==head->next||...
typedef struct list { int data; struct list *next; } ListNode; 2. 实现一个函数,用于遍历并打印单链表中的所有元素 接下来,我们需要实现一个函数来遍历并打印单链表中的所有元素。这个函数将从头节点开始,沿着链表遍历,直到遇到空指针。 c void printList(ListNode *head) { ListNode *current = head; ...
在O(1)时间内删除链表结点。 题目:给定链表的头指针和一个结点指针,在O(1)时间删除该结点。链表结点的定义如下: struct ListNode { int m_nKey; ListNode* m_pNext; }; 函数的声明如下: void DeleteNode(ListNode* pListHead, ListNode* pToBeDeleted);...
做单链表反转题目,报错:member access within null pointer of type ‘struct ListNode’ 题目链接:LINK 问题描述 我明明在初始化指针时候,已经处理了n2->next情况却依然报错 这个报错提示含义是:大概就是他给你传个空指针的话你的语法是错误的含义。
struct ListNode* deleteDuplicates(struct ListNode* head ) { if (head == NULL || head-gt;next == NULL) { return head; _牛客网_牛客在手,offer不愁