String to Integer (atoi) Implementatoito convert a string to an integer. Hint:Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes:It is intended for this problem to be specified vaguely (ie...
Output: -2147483648 Explanation: The number "-91283472332" is out of the range of a 32-bit signed integer. Thefore INT_MIN (−231) is returned. 来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/string-to-integer-atoi 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明...
https://github.com/grandyang/leetcode/issues/8 类似题目: Reverse Integer Valid Number 参考资料: https://leetcode.com/problems/string-to-integer-atoi/ https://leetcode.com/problems/string-to-integer-atoi/discuss/4654/My-simple-solution https://leetcode.com/problems/string-to-integer-atoi/discus...
Java 解法: publicclassSolution {publicintmyAtoi(String str) {if(str.isEmpty())return0;intsign = 1, base = 0, i = 0, n =str.length();while(i < n && str.charAt(i) == ' ') ++i;if(str.charAt(i) == '+' || str.charAt(i) == '-') { sign= (str.charAt(i++) == '...
Can you solve this real interview question? String to Integer (atoi) - Implement the myAtoi(string s) function, which converts a string to a 32-bit signed integer. The algorithm for myAtoi(string s) is as follows: 1. Whitespace: Ignore any leading whi
本文关键词:字符串转整数,atoi,题解,Leetcode, 力扣,Python, C++, Java 目录 题目描述 题目大意 解题方法 代码 日期 题目地址:https://leetcode-cn.com/problems/string-to-integer-atoi/ ...
Can you solve this real interview question? Reverse Words in a String III - Given a string s, reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: s = "Let's take
请注意,你可以假定字符串里不包括任何不可打印的字符。 示例: 输入: "Hello, my name is John" 输出: 5 解释: 这里的单词是指连续的不是空格的字符,所以 "Hello," 算作 1 个单词。 题目难度:简单 通过次数:112.2K 提交次数:295.2K 贡献者:LeetCode 相关标签 ...
注意溢出问题==>Integer.MAX_VALUE 或者 Integer.MIN_VALUE 代码 java public class Solution008 { public int myAtoi(String str) { if (str == null) return 0; str = str.trim(); if ("".equals(str)) return 0; StringBuilder sb = new StringBuilder(); ...
想了想还是用leetcode吧,测试用例更加严谨一些,lintcode的题有些描述有问题,有些测试用例不够完善。 原题链接 题目: 将字符串转换为数字。 从第一个非空格的字符串开始处理到第一个非数字字符结束,如果str[0]是+/-,则将数字转换成对应的正负数;如果是数字,直接转换成对应正数;如果str[0]是非数字字符,直接返...