请你来实现一个myAtoi(string s)函数,使其能将字符串转换成一个 32 位有符号整数(类似 C/C++ 中的atoi函数)。 函数myAtoi(string s)的算法如下: 读入字符串并丢弃无用的前导空格 检查下一个字符(假设还未到字符末尾)为正还是负号,读取该字符(如果有)。 确定最终结果是负数还是正数。 如果两者都不存在,则...
2、直接把num设置成long型, 先num = num * 10 + (str.charAt(start) - '0'); //得到的是两个字符的ascii码的差值,兑换成相应的字符,而不是两个字符相减。 再判断num>Integer.MAX_VALUE或者num<Integer.MIN_VALUE 最后要转换成int类型。 public class StringtoInteger { public static int myAtoi(String...
Can you solve this real interview question? String to Integer (atoi) - Implement the myAtoi(string s) function, which converts a string to a 32-bit signed integer. The algorithm for myAtoi(string s) is as follows: 1. Whitespace: Ignore any leading whi
Can you solve this real interview question? String to Integer (atoi) - Implement the myAtoi(string s) function, which converts a string to a 32-bit signed integer. The algorithm for myAtoi(string s) is as follows: 1. Whitespace: Ignore any leading whi
请你来实现一个 myAtoi(string s) 函数,使其能将字符串转换成一个 32 位有符号整数(类似 C/C++ 中的 atoi 函数)。 函数myAtoi(string s) 的算法如下: 读入字符串并丢弃无用的前导空格 检查第一个字符(假设还未到字符末尾)为正还是负号,读取该字符(如果有)。 确定最终结果是负数还是正数。 如果两者都不...
Leetcode:8.string-to-integer-atoi(字符串转整数),再也不强行装逼要题目的英文描述,好多条件都没看出来,第一遍照着样例打的,错误一堆;应该还能剪枝下;#include<iostream>usingnamespacestd;intmyAtoi(stringstr){longlongresult=0;boolflag1=false,flag2=false;for(i.
今天的题目是(8. String to Integer (atoi))[https://leetcode.com/problems...] 题目描述: Implement atoi which converts a string to an integer. The function first discards as many whitespace characters as necessary until the first non-whitespace character is found. Then, starting from this char...
return Integer.MIN_VALUE; return (int) result; } public static void main(String[] args) { Solution solution=new Solution(); System.out.println(solution.myAtoi("2147483648")); } } 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11.
1. 题目 Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended for this problem to be specified vaguely (ie, no given...
* @链接:https://leetcode-cn.com/problems/string-to-integer-atoi/solution/8-zi-fu-chuan-zhuan-huan-zheng-shu-atoi-by-liu-zi-/ * @param {string} str * @return {number} */varmyAtoi=function(str){str=str.trim();if(!/^[+|-]?\d+/.test(str))return0;letval=parseInt(str.match(...