在C++编程中,遇到“string does not name a type”的错误信息通常意味着编译器无法识别string作为一个类型。这个错误可能由多种原因引起,下面是对该错误的详细解释、常见原因及解决方法。 1. 错误信息含义 “string does not name a type”错误表明编译器在编译代码时,无法将string识别为一个有效的类型。这通常是...
C++ error: 'string' does not name a type include一个定义结构体的文件typedef.h 编译出现了error: 'string' does not name a type 查资料http://blog.csdn.net/niro_z/article/details/8028996得到提示, 要在string改为std::string就OK了。 但是这样还是有点别扭,于是这么改 usingnamespacestd; #include"...
#include<string>std::stringxx;此时报错stringnosuchfileordirectory,修改成#include<string.h>std::stringxx;此时报错'string'doesnotnameatype问题已经解决:#include<string>下面... #include <string>std::string xx;此时报错string no such file or directory,修改成#include <string.h>std::string xx;此时报...
When I try to compile this I get the error message "String does not name a type." Also, I get the message "'Choices' was not declared in this scope." I don't understand why I am getting either of these errors. May 15, 2008 at 4:26am ...
import java.io.*; abstract class animal{ String name; String type; 可能函数是有返回值的,不是空类型的.还是看看代码吧.
解决办法:string in namespace std does not name a type,在C改成CPP的时候,经常报类似错误.怎么办?#include<string>//类似的还有:#include<list>#include<vector>#include<map>
Forum Beginners string does not name a type string does not name a typeJul 21, 2009 at 9:23am Nelo87 (19) I already searched in google on how to fix this problem, but I still get the error.I was using "using namespace std;" at first. I changed that for the following, because ...
‘string’ does not name a type static string UTF32ToUTF8(const std::vector<char32>& str32); ^ software/DocCreator/CMakeFiles/DocCreator.dir/build.make:1826 : la recette pour la cible « software/DocCreator/CMakeFiles/DocCreator.dir/src/FontGenerator/OCRDialog.cpp.o » a échouée...
'string' does not name a type Last edited onMar 9, 2012 at 5:47am Mar 9, 2012 at 5:47am LB(13399) Change "string" to "std::string" Most likely you did not mean to comment out line 12. Also, what your professor told you only applies when you have optimizations on - in debug...
I am getting an error stating that error: ‘String’ does not name a type and I do not know why as why I am getting this error message. The error indicates at new string on line 8. Any ideas why this is happening? 1 2 3