解决办法:string in namespace std does not name a type,在C改成CPP的时候,经常报类似错误.怎么办?#include<string>//类似的还有:#include<list>#include<vector>#include<map>
C:\Users\Derv\Desktop\Census\QuestsAndAnswers.cpp|25|error:'string'does not name a type| I tried fixing it by adding#include <string>, using namespace std and by even usingstd::stringbut for some reason, it still gives the error. ...
#include<string>std::stringxx;此时报错stringnosuchfileordirectory,修改成#include<string.h>std::stringxx;此时报错'string'doesnotnameatype问题已经解决:#include<string>下面... #include <string>std::string xx;此时报错string no such file or directory,修改成#include <string.h>std::string xx;此时报...
'string' does not name a type Last edited onMar 9, 2012 at 5:47am Mar 9, 2012 at 5:47am LB(13399) Change "string" to "std::string" Most likely you did not mean to comment out line 12. Also, what your professor told you only applies when you have optimizations on - in debug...
1.androidERROR:unknownvirtualdevicename解决法打开系统属性-->环境变量—>在“系统变量”那一个GroupBox下面选择“新建”-->变量名为"ANDROID_SDK_HOME”(注意，这个变量名不能改变，只能是这个名字！)，然后把变量值改为你想把AVD所在的".android”文件夹放置的位置，比如："F:\AndroidEmulator”，在...
‘string’ does not name a type static string UTF32ToUTF8(const std::vector<char32>& str32); ^ software/DocCreator/CMakeFiles/DocCreator.dir/build.make:1826 : la recette pour la cible « software/DocCreator/CMakeFiles/DocCreator.dir/src/FontGenerator/OCRDialog.cpp.o » a éch...
a string constant to 'char*' [-Wwrite-strings] 277 348 | return "Unknown error"; 278 | ^~~~ 279 In file included from rempi_recorder.h:48, 280 from rempi_recorder.cpp:31: >> 281 rempi_message_manager.h:53:3: error: 'string' does not name a type; did you mean 'stdin'? 282...
The Compare(String, Int32, String, Int32, Int32, StringComparison) method does not consider these characters when it performs a linguistic or culture-sensitive comparison. To recognize ignorable characters in your comparison, supply a value of Ordinal or OrdinalIgnoreCase for the comparisonType ...
Returns the position of the first occurrence of the target stringxin the queried stringy. If the target stringxdoes not exist in the queried stringy,0is returned. Syntax INTEGER POSITION(x IN y) Parameters x: string y: string. Example ...
"<none>" : filename); filename = ExtractFilename("delegate.txt"); Console.WriteLine("{0}", String.IsNullOrEmpty(filename) ? "<none>" : filename); filename = ExtractFilename(@"C:\temp\notafile.txt"); Console.WriteLine("{0}", String.IsNullOrEmpty(filename) ? "<none>" : file...