vector<MyClass> vec; std::thread thread_attach([&vec]() { for (size_t i = 0; i < 100; i++) { MyClass myclass; myclass.id = 100; vec.emplace_back(myclass); }; }); std::thread thread_get([&vec]() { for (size_t i = 0; i < 100; i++) { std::cout << ...
求助,std::ve..如题,编译器为mingw,未使用cmake,其他都好好的,补充:vs2022中可运行,如果gcc实在不行,如何在vscode中设置与vs2022一样的环境(编译选项)呢
//读写锁DEMO #include <iostream> #include <thread> #include <shared_mutex> //本次重点 #include <vector> #include <chrono> #include <mutex> // 包含 std::unique_lock std::shared_mutex shared_mtx; int shared_data =0 ; // 要修改和读取的数据 //-读取数据 --id参数只是一个假设按照主键...
const int num_consumers = 2; std::vector<std::thread> producers; std::vector<std::thread> consumers; for (int i = 0; i < num_producers; ++i) { producers.emplace_back(producer, i); } for (int i = 0; i < num_consumers; ++i) { consumers.emplace_back(consumer, i); } for (...
std::vector<std::thread> threads; // 启动10个线程,每个线程对 counter 执行 100 次 increment 操作 for(inti =0; i <10; ++i) { threads.emplace_back(thread_func, counter,std::ref(mtx)); } // 等待所有线程完成 for(auto& t : threads) { ...
std::vectorv; v.push_back(0); v.emplace_back(1); 1. 2. 3. 4. 6.使用 tuple 对于两个不同类型的元素可以用: std::pairpi = std::make_pair(1, 'a'); std::cout << pi.first << " " << pi.second << std::endl; 1. ...
lst.push_back(i); mtx.unlock(); std::this_thread::sleep_for(std::chrono::milliseconds(3)); } }voidoutMsg() {while(true) {intnum =0; mtx.lock();if(!lst.empty()) { num=lst.front(); lst.pop_front(); std::cout<<"remove element:"<< num <<std::endl; ...
::vector<std::thread> threadList; threadList.reserve(threadNums); // 1 创建 threadNums 个线程 for(int idx=0; idx < threadNums; ++idx) { threadList.emplace_back(std::thread{do_some_work, idx}); } std::cout<<"work in main thread"...
std::vector<decltype(model.Clone())> models;for(inti =0; i < thread_num; ++i) { models.emplace_back(std::move(model.Clone())); } std::vector<std::thread> threads;for(inti =0; i < thread_num; ++i) { threads.emplace_back(Predict, models[i].get(), i);//std::thread thread...
"" : "\n"); std::atomic_store_explicit(&lock, false, std::memory_order_release); } } int main() { std::vector<std::thread> v; for (int n = 0; n < 8; ++n) v.emplace_back(f, n); for (auto& t : v) t.join(); } 可能的输出: 02222222222222222222222002222222222222222222222...