std::chrono::steady_clock 为了表示稳定的时间间隔,后一次调用now()得到的时间总是比前一次的值大(这句话的意思其实是,如果中途修改了系统时间,也不影响now()的结果),每次tick都保证过了稳定的时间间隔。 操作有: now() 获取当前时钟 典型的应用是给算法计时: 1 // steady_clock example 2 #include <iostr...
1//steady_clock example2#include <iostream>3#include <ctime>4#include <ratio>5#include <chrono>67intmain ()8{9usingnamespacestd::chrono;1011steady_clock::time_point t1 =steady_clock::now();1213std::cout <<"printing out 1000 stars...\n";14for(inti=0; i<1000; ++i) std::cout <...
period 表示时钟计次周期的 std::ratio 类型,单位为秒 duration std::chrono::duration<rep, period> time_point std::chrono::time_point<std::chrono::steady_clock> 成员常量 constexpr bool is_steady [静态] 稳定时钟标志,始终为 true (公开静态成员常量) 成员函数 now [静态] 返回表示当前时钟...
#include<iostream>#include<chrono>#include<ctime>intmain(){std::cout<<"Current time: "<<std::chrono::steady_clock::now().time_since_epoch()<<" seconds"<<std::endl;autot1=std::chrono::steady_clock::now();autot2=std::chrono::steady_clock::now()+std::chrono::seconds(1);std::cou...
std::chrono::system_clock::now().time_since_epoch().count(); 2、std::chrono::steady_clock::now() 功能:获取系统时间戳,单位纳秒(nanosecond) 使用方法: std::chrono::steady_clock::now().time_since_epoch().count(); 3、gettimeofday
count() << std::endl; // 以秒为单位输出当前时间 std::this_thread::sleep_for(dur); std::cout << std::chrono::time_point_cast<std::chrono::seconds> (std::chrono::steady_clock::now()) .time_since_epoch().count() << std::endl; // 以秒为单位输出当前时间 return 0; } 这段...
staticstd::chrono::time_point<std::chrono::steady_clock>now()noexcept; (since C++11) Returns a time point representing the current point in time. Return value A time point representing the current time. Example Run this code #include <chrono>#include <cstddef>#include <iomanip>#include <ios...
Describe the bug I encountered an overflow issue with std::chrono::steady_clock::now() after ~923 seconds (~15 minutes). Just copied some source from the original implementation to demonstrate the issue. Test sample #include <cassert> #i...
auto end = std::chrono::steady_clock::now(); std::chrono::duration<double> elapsed_seconds = end - start; printDuration(elapsed_seconds); return 0; } 在这个示例中,printDuration方法接受一个std::chrono::duration<double>类型的参数,表示以秒为单位的时间间隔。在main函数中,我们测量了从st...