std::string>map1={{1,"one"},{2,"two"}};std::map<int,std::string>map2={{3,"three"},{4,"four"}};map1.merge(map2);// 将map2中的所有元素合并到map1for(constauto&pair:map1){std::cout<<pair.first<<": "<<pair.second<<std::endl;}return0;}...
若任何等价的值在第一范围出现n次,在第二范围出现m次,则std::merge会输出所有n+m次出现,而std::set_union将只输出std::max(n, m)次。故std::merge准确输出std::distance(first1, last1)+std::distance(first2, last2)个值,而std::set_union可能产生得更少。
如果出现任何等效值n在第一个范围内m第二次,std::merge会输出所有n+m发生情况std::set_union会输出std::max(n, m)只有一个。所以std::merge精确输出std::distance(first1, last1)+std::distance(first2, last2)价值观和std::set_union可能产生的更少。
return std::copy(first1, last1, std::copy(first2, last2, result)); } int main() { std::vector<int> numbers1 = {1, 3, 5, 7, 9}; std::vector<int> numbers2 = {2, 4, 6, 8, 10}; std::vector<int> merged(numbers1.size() + numbers2.size()); myMerge(numbers1.begin(...
如果作为算法一部分调用的函数的执行抛出异常,且ExecutionPolicy是标准策略之一,那么调用std::terminate。对于任何其他ExecutionPolicy,行为由实现定义。 如果算法无法分配内存,那么抛出std::bad_alloc。 可能的实现 参阅libstdc++与libc++中的实现。 merge (1)
std::sort(work_tasks.begin(), work_tasks.end(), cmp); // Create another vector, which is big enough to accept the 2 vectors. todos_t merged_tasks(personal_tasks.size() + work_tasks.size(), std::shared_ptr<task>()); std::merge(personal_tasks.begin(), personal_tasks.end(), wor...
merge Create account std::merge Defined in header<algorithm> template<classInputIt1,classInputIt2,classOutputIt> OutputIt merge(InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, OutputIt d_first); (1)(constexpr since C++20)...
template<class C2> void merge( std::multiset<Key, C2, Allocator>& source ); (3)(since C++17) template<class C2> void merge( std::multiset<Key, C2, Allocator>&& source ); (4)(since C++17) Attempts to extract ("splice") each element insourceand insert it into*thisusing the comparis...
voidmerge(std::multimap<Key, T, C2, Allocator>&&source); (4)(C++17 起) 试图释出(“接合”)source中每个元素,并用*this的比较对象插入到*this。 若*this中有元素,其关键等价于来自source中元素的关键,则不从source释出该元素。 不复制或移动元素,只会重指向容器结点的内部指针。指向被转移元素的所有指...
suingstd::merge. Since that algorithm works only with iterators and only STL containers have iterators, one acceptable solution would be to save the files' contents into two STL containers and then merge the two usingstd::merge. Finally we can write the merged data back into a third text ...