对于类成员函数、lambda表达式或其他可调用对象就无能为力了，因此，C++11推出了std::function与std::...
std::map<Key,T,Compare,Allocator>::rbegin, std::map<Key,T,Compare,Allocator>::crbegin std::map<Key,T,Compare,Allocator>::rend, std::map<Key,T,Compare,Allocator>::crend std::map<Key,T,Compare,Allocator>::empty std::map<Key,T,Compare,Allocator>::size std::map<Key,T,Compare,Allocato...
<cpp |container |map C++ size_type size()const; (noexcept since C++11) Returns the number of elements in the container, i.e.std::distance(begin(), end()). Parameters (none) Return value The number of elements in the container. ...
在GCC/libstdc实现中，max_size在include/bits/stl_map.h上定义为
Possible output: Maximum size of a std::unordered_map is 768,614,336,404,564,650 See also size returns the number of elements (public member function)
I was trying to ensure that astd::maphas the same size as anenumclass at compile time. Avoiding the use of macros, if possible. I tried withstatic_assert, but reading Stack Overflow I concluded that it can't be done becausestd::mapis "constructed" at runtime. Or ...
C++ 容器库 std::unordered_map size_type bucket_size( size_type n ) const; (C++11 起) 返回下标为 n 的桶中的元素数。 参数n - 要检验的桶的下标 返回值桶n 中的元素数。 复杂度与桶n 的大小成线性。 参阅bucket_count 返回桶数 (公开成员函数) ...
您需要对类中的std::unordered_map进行braced-init-list（或统一初始化）。
#include<unordered_map> #include<algorithm> #include<cctype> using namespace std; int main(){ unordered_map<string,size_t> word_count; string word; while(cin>>word){ for(size_t i=0;i<word.size();++i){ word[i]=tolower(word[i]); ...
std::map<Key,T,Compare,Allocator>::max_size std::map<Key,T,Compare,Allocator>::insert std::map<Key,T,Compare,Allocator>::emplace_hint std::map<Key,T,Compare,Allocator>::erase std::map<Key,T,Compare,Allocator>::swap std::map<Key,T,Compare,Allocator>::count std::map<Key,T,Compare...