SELECTe.EmployeeName,SUM(DATEDIFF(HOUR,w.StartTime,w.EndTime))ASTotalWorkHoursFROMEmployees eJOINWorkHours wONe.EmployeeID=w.EmployeeIDWHEREw.WorkDate>=DATEADD(DAY,-7,GETDATE())GROUPBYe.EmployeeName; 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 结尾 SQL Server 为时间和日期数据的管理提供了...
这段代码使用循环插入日期和时间数据。我们需要指定起始日期和结束日期,并且使用DATEADD函数将日期逐一递增。然后,通过选择Hours子查询中的小时数,将日期和小时数据插入到临时表中。 步骤3:查询日历表 一旦我们将日期和时间数据插入到临时表中,我们就可以使用以下代码查询日历表以获取所需的结果: SELECT*FROM#Calendar 1...
复制 保存Select dateadd(ms,-3,DATEADD(yy, DATEDIFF(yy,0,getdate()), 0)) 8.本月的最后一天 复制 保存Select dateadd(ms,-3,DATEADD(mm, DATEDIFF(m,0,getdate())+1, 0)) 9.本年的最后一天 复制 保存Select dateadd(ms,-3,DATEADD(yy, DATEDIFF(yy,0,getdate())+1, 0)) 10.本月的第一...
DECLARE @intMaxHours AS INT; SET @intMaxHours = dbo.ufn_Hours(dbo.ufn_GetMaxDateTime()); IF @intHours >= @intMaxHours BEGIN SET @intHours = @intMaxHours; END RETURN DATEADD(HOUR, @intHours, dbo.ufn_GetDefaultBasedate()); END GO IF OBJECT_ID(N'dbo.ufn_HoursOfDay', 'FN') IS...
GROUP BY DATEADD(dd, DATEDIFF(dd, 0, EventDateTime), 0),EventType Sample Result: --非常感谢您的见解 请尝试以下操作,说明在查询注释中: /* A recursive CTE to get the 24 hours from '00:00:00' to '23:00:00:' */ with all_day_hours as ...
DATEADD(dd, -@days, @date2) < @date1 SELECT @days = @days - 1; SET @date2 = DATEADD(dd, -@days, @date2); SELECT @hours = DATEDIFF(hh, @date1, @date2); IF DATEADD(hh, -@hours, @date2) < @date1 SELECT @hours = @hours - 1; SET @date2 = DATEADD(hh, -@hours, @...
timeOnly.AddHours(value)DATEADD(hour, , @value@timeOnly)EF Core 8.0 timeOnly.AddMinutes(value)DATEADD(minute, , @value@timeOnly)EF Core 8.0 timeOnly.HourDATEPART(hour, @timeOnly)EF Core 8.0 timeOnly.IsBetween(start, end)@timeOnly >= @start AND @timeOnly<@endEF Core 8.0 ...
(dd, @date1, @date2); IF DATEADD(dd, -@days, @date2) < @date1SELECT@days= @days-1;SET@date2 =DATEADD(dd, -@days, @date2);SELECT@hours=DATEDIFF(hh, @date1, @date2); IF DATEADD(hh, -@hours, @date2) < @date1SELECT@hours= @hours-1;SET@date2 =DATEADD(hh, -@hours, ...
DATEADD(dd, -@days, @date2) < @date1 SELECT @days = @days - 1; SET @date2 = DATEADD(dd, -@days, @date2); SELECT @hours = DATEDIFF(hh, @date1, @date2); IF DATEADD(hh, -@hours, @date2) < @date1 SELECT @hours = @hours - 1; SET @date2 = DATEADD(hh, -@hours, @...
(dd, @date1, @date2); IF DATEADD(dd, -@days, @date2) < @date1SELECT@days= @days-1;SET@date2 =DATEADD(dd, -@days, @date2);SELECT@hours=DATEDIFF(hh, @date1, @date2); IF DATEADD(hh, -@hours, @date2) < @date1SELECT@hours= @hours-1;SET@date2 =DATEADD(hh, -@hours, ...