In SQL Server there is anIF…ELSE control flow statement. However, it cannot be used inside a SELECT statement. The closest of IF…THEN operation which can be used in SELECT statements is CASE expression or the IIF function. Let us see how to use CASE and IIF using an example. For thi...
For more information, seeIIF Function Query Hints in SQL Server Analysis Services 2008andExecution Plans and Plan Hints for MDX IIF Function and CASE Statement. Examples The following query shows a simple use ofIIFinside a calculated measure to return one of two different string values when the ...
1 SELECT IIF(5 > 3, 'TRUE', 'FALSE' ) Example 2: SQL IIF statement with variablesIn the following example, we specified two integer variables and assigned values. We use variables for comparison in the IIF statement. 1 2 DECLARE @A INT = 80, @B INT = 70 SELECT IIF(@A >= @B,...
The result of this statement is an error. C. IIF with NULL parameters SQL DECLARE@PINT=NULL, @SINT=NULL;SELECT[Result] =IIF(45>30, @P, @S ); Here is the result set. Result --- NULL Next steps CASE (Transact-SQL) CHOOSE (
SELECT IIF ( 45 > 30, NULL, NULL ) AS Result; The result of this statement is an error.C. IIF with NULL parametersCopy DECLARE @P INT = NULL, @S INT = NULL; SELECT IIF ( 45 > 30, @p, @s ) AS Result; Here is the result set.Copy ...
UNION [ALL] selectstatement [UNION [ALL] selectstatement][…n]其中selectstatement为待联合的SELECT查询语句。 ALL选项表示将所有行合并到结果集合中。不指定该项时,被联合查询结果集合中的重复行将只保留一行。 联合查询时,查询结果的列标题为第一个查询语句的列标题。因此,要定义列标题必须在第一个查询语 ...
SELECT[Result] =IIF(45>30,NULL,NULL); The result of this statement is an error. C. IIF with NULL parameters SQL DECLARE@PINT=NULL, @SINT=NULL;SELECT[Result] =IIF(45>30, @P, @S ); Here's the result set. Result --- NULL Next steps...
For more information, seeIIF Function Query Hints in SQL Server Analysis Services 2008andExecution Plans and Plan Hints for MDX IIF Function and CASE Statement. Examples The following query shows a simple use ofIIFinside a calculated measure to return one of two different string values when the ...
SELECT IIF ( 45 > 30, NULL, NULL ) AS Result; The result of this statement is an error.C. IIF with NULL parametersCopy DECLARE @P INT = NULL, @S INT = NULL; SELECT IIF ( 45 > 30, @p, @s ) AS Result; Here is the result set.Copy ...
IIF(<condition>,<expression if true>,<expression if false>) It’s a shorthand for a searched CASE. Let’s rewrite the following statement: SELECT [BusinessEntityID],[MaritalStatus],MaritalStatusDesc=CASE WHEN [MaritalStatus]='S'THEN'Single'ELSE'Married'END ...