SQL Copy 4) IIF Function with data type precedence SELECT IIF(21 < 11, 551.50, 551) Result SQL Copy 5) IIF Function with NULL A) With NULL Constants If we specify "NULL" in true_value and false_value, this statement will result in an error. SELECT IIF( 25 * 12 = 300, NULL, NU...
Internally SQL Server converts the statement into the CASE statement and executes. We can check it using the actual execution plan of a query. Execute the query from Example 6 with an Actual execution plan. In the actual execution plan, look at the properties of Compute Scalar. You can see...
1回答 查找与SQL "IN“子句相同的SSRS筛选器 、 我正在尝试为我的SSRS报告中的一个字段设置条件格式。可更改字体颜色的基本格式。这是我在报表生成器中的原始表达式: IIf("ex1"=Fields!ID_name“值执行此操作,这些值都共享共同的”delta值“。我想知道是否有类似于SQL<e 浏览9提问于2017-08-15得票数 0 2...
SQL Copy SELECT [Result] = IIF( 45 > 30, NULL, NULL ); The result of this statement is an error. C. IIF with NULL parameters SQL Copy DECLARE @P INT = NULL, @S INT = NULL; SELECT [Result] = IIF( 45 > 30, @P, @S ); Here is the result set. Copy Result --- ...
Returns one of two values, depending on whether the Boolean expression evaluates to true or false in SQL Server 2012.Transact-SQL Syntax ConventionsSyntaxCopy IIF ( boolean_expression, true_value, false_value ) Argumentsboolean_expression A valid Boolean expression. If this argument is not a Boo...
For more information, seeIIF Function Query Hints in SQL Server Analysis Services 2008andExecution Plans and Plan Hints for MDX IIF Function and CASE Statement. Examples The following query shows a simple use ofIIFinside a calculated measure to return one of two different string values when the ...
Returns a value of any data type with the highest precedence from true_value and false_value. Note: TheIIF()function is similar to a case statement. Example 1: In the following example, theIIF()function evaluates a boolean expression10 < 20. Since 10 is less than 20, it retuns 'TRUE'...
The result of this statement is an error. C. IIF with NULL parameters Copy DECLARE @P INT = NULL, @S INT = NULL; SELECT IIF ( 45 > 30, @p, @s ) AS Result; Here is the result set. Copy Result --- NULL (1 row(s) affected) See Also...
SQL DECLARE@aINT=45, @bINT=40;SELECT[Result] =IIF( @a > @b,'TRUE','FALSE'); Here's the result set. Result --- TRUE B. IIF with NULL constants SQL SELECT[Result] =IIF(45>30,NULL,NULL); The result of this statement is an error. C. IIF...
SQL Copy SELECT [Result] = IIF( 45 > 30, NULL, NULL ); The result of this statement is an error. C. IIF with NULL parameters SQL Copy DECLARE @P INT = NULL, @S INT = NULL; SELECT [Result] = IIF( 45 > 30, @P, @S ); Here's the result set. Copy Result --- ...