方法二:SQL实现方法之一般函数写法 相比较第一种正则函数的方法,普通的sql函数比较通用化,各个版本都支持。但写法稍复杂 select substr(inlst, instr(inlst, ',', 1, rownum) +1, instr(inlst, ',', 1, rownum +1) - instr(inlst, ',', 1, rownum) -1) from
SQL中的split方法的使用 参数说明: 1、@String :需要split的字符串 2、@Delimiter:格式化时分隔符 3、@index:返回split后数组的值 ALTERFUNCTION[dbo].[GetCount_Split_StrByDelimiter](@StringVARCHAR(8000),@DelimiterCHAR(1),@indexchar(1))RETURNSvarchar(100)ASBEGINDECLARE@temptableTABLE(itemsVARCHAR(8000))...
Real World Example for SQL Split Column by Delimiter Here in the real world, DBA’s are often faced with more complex tables or views and not just a simple two column table as in the above sample. Although the sample above is a great primer for dissecting how to parse a string value, ...
内容提示: SQL 中的 split 方法的使用 参数说明: 1、@String :需要 split 的字符串 2、@Delimiter :格式化时分隔符 3、@index :返回 split 后数组的值 ALTER FUNCTION [dbo].[GetCount_Split_StrByDelimiter](@String VARCHAR(8000), @Delimiter CHAR(1),@index char(1)) RETURNS varchar(100) AS BEGIN...
('apple,banana,orange', ',', -1) AS part3; -- 使用FIND_IN_SET查找特定值 SELECT * FROM table WHERE FIND_IN_SET('banana', 'apple,banana,orange'); -- 自定义SPLIT_STR函数 DELIMITER $$ CREATE FUNCTION SPLIT_STR(x VARCHAR(255), delim VARCHAR(12), pos INT) RETURNS VARCHAR(255) ...
CREATEORREPLACEFUNCTION fn_split (p_strIN CLOB, p_delimiterIN VARCHAR2) RETURN ty_str_split IS jINT := 0; iINT := 1; lenINT := 0; len1INT := 0; str VARCHAR2 (4000); str_split ty_str_split := ty_str_split (); BEGIN ...
2019-12-20 10:42 −Oracle SQL Developer中SQL语句格式化快捷键:1、选中需要格式化的sql;2、Ctrl + F7即可格式化。... annilyn 0 759 oracle自定义split分割函数 2019-12-24 15:06 −函数如下: 1 create or replace FUNCTION fn_rme_split(p_str IN VARCHAR2, 2 p_delimiter IN VARCHAR2) 3 RETURN...
Databricks SQL Databricks Runtime 11.3 LTS 及更高版本 将str围绕delim的次数拆分,并返回partNum部分。 语法 split_part(str, delim, partNum) 参数 str:要拆分的STRING表达式。 delimiter:用作部分分隔符的STRING表达式。 partNum:选择要返回的部分的INTEGER表达式。
Delimiter, @Expression), @dl = len(@Delimiter), @l = len(@Expression) while (@i > 0) begin select @value = ltrim(rtrim(left(@Expression, @i - 1))), @Expression = substring(@Expression, @i + 1, @l) insert into @Values (value) values(@value) select @i = charindex(@Delimiter...
Since I now had to do some math on these values, it was essential to parse these values in a Table. Using the code I started by using a split function from SQLCentral. CREATE FUNCTION [dbo].[Split](@String varchar(8000), @Delimiter char(1)) returns @temptable TABLE (items varchar(80...