classSolution {public: typedeflonglongLL;intm;boolcheck(LL sum, vector<int>ν) { LL nsum=0;intcnt =1;for(inti : nu) {if(i > sum)returnfalse;if(i + nsum >sum) { cnt++; nsum=i; }elsensum+=i; }returncnt <=m; }intsplitArray(vector<int>& nums,intm) {intn =nums.size(...
Given an array which consists of non-negative integers and an integer m, you can split the array into m non-empty continuous subarrays. Write an algorithm to minimize the largest sum among these m subarrays. Note: If n is the length of array, assume the following constraints are satisfied...
leetcode 410. Split Array Largest Sum I saw something really interesting tonight…... So I tried this problem, but failed to figure out the O(n logn) algorithm classSolution{publicintsplitArray(int[] nums,intm){longl=0, r =0;intN=nums.length;for(inti=0; i < N; ++i) { l = M...
代码: classSolution{public:intsplitArray(vector<int>&nums,intm){intn=nums.size();vector<vector<longlong>>f(n+1,vector<longlong>(m+1,LLONG_MAX));vector<longlong>sub(n+1,0);for(inti=0;i<n;i++){sub[i+1]=sub[i]+nums[i];//计算前缀和}f[0][0]=0;for(inti=1;i<=n;i++...
410 Split Array Largest Sum 分割数组的最大值 给定一个非负整数数组和一个整数 m,你需要将这个数组分成 m 个非空的连续子数组。设计一个算法使得这 m 个子数组各自和的最大值最小。 注意: 数组长度 n 满足以下条件: 1≤ n ≤ 1000 1≤ m ≤ min(50, n)...
Given an array which consists of non-negative integers and an integer m, you can split the array into m non-empty continuous subarrays. Write an algorithm to minimize the largest sum among these m subarrays. Note: If n is the length of array, assume the following constraints are satisfied...
Given an integer array nums and an integer k, split nums into k non-empty subarrays such that the largest sum of any subarray is minimized. https://www.youtube.com/watch?v=_k-Jb4b7b_0 Naive DP O(m*n^2) classSolution{public:intsplitArray(vector<int>&nums,intk){constintn=nums....
classSolution{publicintsplitArray(int[]nums,intm){intlen=nums.length;int[][]dp=newint[len][m+1];dp[0][1]=nums[0];for(inti=1;i<len;i++){dp[i][1]=dp[i-1][1]+nums[i];}for(inti=0;i<len;i++){for(intj=2;j<=m;j++){intminSumMax=Integer.MAX_VALUE;for(intk=0;k...
https://leetcode.com/problems/split-array-largest-sum/discuss/89817 Solution: 思路: Use binary search to approach the correct answer. We have l = max number of array; r = sum of all numbers in the array;Every time we do mid = (l + r) / 2; ...
i managed to get this far but my problem now is whenever i sort the COUNTIF column by largest to smallest it errors a prompt "you cant change part of an array" ive tried changing it to text data or copying and pasting but it yields same ...