typedeflonglongLL;intm;boolcheck(LL sum, vector<int>ν) { LL nsum=0;intcnt =1;for(inti : nu) {if(i > sum)returnfalse;if(i + nsum >sum) { cnt++; nsum=i; }elsensum+=i; }returncnt <=m; }intsplitArray(vector<int>& nums,intm) {intn =nums.size();this->m =m; LL ...
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leetcode 410. Split Array Largest Sum I saw something really interesting tonight…... So I tried this problem, but failed to figure out the O(n logn) algorithm classSolution{publicintsplitArray(int[] nums,intm){longl=0, r =0;intN=nums.length;for(inti=0; i < N; ++i) { l = M...
Given an array which consists of non-negative integers and an integer m, you can split the array into m non-empty continuous subarrays. Write an algorithm to minimize the largest sum among these m subarrays. **Note:**If n is the length of array, assume the following constraints are sati...
一、原题:410. Split Array Largest Sum 方法一、动态规划 「将数组分割为mm段,求……」是动态规划题目常见的问法。 f[i][j]: 表示将数组的前i个数分割为j段所能得到的最大连续子数组和的最小值。 sub(i,j): 表示数组nums中下标落在区间[i,j]内的数的和。
410 Split Array Largest Sum 分割数组的最大值 给定一个非负整数数组和一个整数 m,你需要将这个数组分成 m 个非空的连续子数组。设计一个算法使得这 m 个子数组各自和的最大值最小。 注意: 数组长度 n 满足以下条件: 1≤ n ≤ 1000 1≤ m ≤ min(50, n)...
Given an array which consists of non-negative integers and an integer m, you can split the array into m non-empty continuous subarrays. Write an algorithm to minimize the largest sum among these m subarrays. Note:If n is the length of array, assume the following constraints are satisfied:...
Given an array which consists of non-negative integers and an integer m, you can split the array into m non-empty continuous subarrays. Write an algorithm to minimize the largest sum among these m subarrays. Note: If n is the length of array, assume the following constraints are satisfied...
Leetcode 410 Split Array Largest SumGiven an array which consists of non-negative integers and an integer m, you can split the array into m non-empty continuous subarrays. Write an algorithm to mini…
public class SplitArray { public static void main(String[] args) {} //https://leetcode.com/problems/split-array-largest-sum/description/ public int splitArray(int[] nums, int m) { int start = 0; int end = 0;for (int i = 0; i < nums.length; i++) { ...