}intn = matrix[0].length;//columns//total rounds can be calculatd by using thisintrounds = (Math.min(m,n)+1)/2;for(inti=0; i<rounds; i++){//corresponding rowintcRow = m-i-1;//corresponding columnintcColumn = n-i-1;//corresponding row equals current rowif(i ==cRow){for(i...
代码实现: vector<int> spiralOrder(vector<vector<int>>& matrix) { vector<int> ans; if (matrix.empty()) return ans; int left = 0, top = 0, right = matrix[0].size() - 1, bottom = matrix.size() - 1; while(left <= right && top <= bottom){ for(int i = left; i <= righ...
LeetCode 54. Spiral Matrix 程序员木子 香港浸会大学 数据分析与人工智能硕士在读 来自专栏 · LeetCode Description Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order. Example 1: Input:[[ 1, 2, 3 ],[ 4, 5, 6 ],[ 7, ...
5 vector<int> rlt; 6 int m =matrix.size(); 7 if (m<=0) 8 return rlt; 9 int n = matrix[0].size(); 10 if (n<=0) 11 return rlt; 12 int flag[4] = {0, m-1, 0, n-1}; 13 int direction = 0; //left 2 right; 14 int i = 0; 15 while (true){ 16 int j = ...
Can you solve this real interview question? Spiral Matrix - Given an m x n matrix, return all elements of the matrix in spiral order. Example 1: [https://assets.leetcode.com/uploads/2020/11/13/spiral1.jpg] Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
https://leetcode.com/problems/spiral-matrix/ 思路1 循环矩阵的左上角 这里我的思路就是 以 左上角 i,j = 0,0为初始点,然后每次都从对角线下移,一直到越界或者matrix[i][j]已经在res里面。这里每次都要记录start_i, start_j,即左上角点,以及end_i, end_j右下角点。
https://leetcode.com/problems/spiral-matrix-ii/ 对于Spiral Matrix II, 这里我们只需要首先建立一个n*n的matrix,然后像I一样遍历即可。 上code class Solution(object): def generateMatrix(self, n): """ :type n: int :rtype: List[List[int]] ...
Can you solve this real interview question? Spiral Matrix - Given an m x n matrix, return all elements of the matrix in spiral order. Example 1: [https://assets.leetcode.com/uploads/2020/11/13/spiral1.jpg] Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
【CSON】LeetCode:885. Spiral Matrix III 0 0 2022-03-10 19:12:38未经作者授权,禁止转载点赞投币收藏分享官方网站:www.cspiration.com 微信号:cspiration01 微信公众号:北美CS求职 知识 职业职场 算法 留学生 程序员面试 北美留学 数据结构 leetcode 北美求职 算法题 程序员求职 北美...
vector<int> spiralOrder(vector<vector<int>>& matrix) { if(matrix.empty() || matrix[0].empty()) return {}; int n = matrix.size(); int m = matrix[0].size(); int c = m>n? n/2:m/2; vector<int> ret; for(int i=0; i<c; i++){ ...