直接看代码了: 1publicclassSolution {2publicList<Integer> spiralOrder(int[][] matrix) {3ArrayList<Integer> result=newArrayList<Integer>();4if(matrix ==null|| matrix.length == 05|| matrix[0].length == 0) {6returnresult;7}8intm=matrix.length,n=matrix[0].length;9intstartX=0,startY=0...
classSolution{public:vector<int>spiralOrder(vector<vector<int>>& matrix){//0.函数入口判断vector<int> temp;if(!matrix.size())returntemp;//1.计算行列数intstart=0;introws=matrix.size();intcols=matrix[0].size();vector<int>ret(rows*cols); ret.clear();//2.打印循环while(start<<1<rows&&...
Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order. Example 1: Input:[[ 1, 2, 3 ],[ 4, 5, 6 ],[ 7, 8, 9 ]]Output: [1,2,3,6,9,8,7,4,5]Example 2: Input:[[1, 2, 3, 4],[5, 6, 7, 8],[9,10,11,12...
代码实现: vector<int> spiralOrder(vector<vector<int>>& matrix) { vector<int> ans; if (matrix.empty()) return ans; int left = -1, top = -1, right = matrix[0].size(), bottom = matrix.size(); int x = 0, y = -1, dx = 0, dy = 1, cnt = right * bottom; while(cnt--...
https://leetcode.com/problems/spiral-matrix/ 思路1 循环矩阵的左上角 这里我的思路就是 以 左上角 i,j = 0,0为初始点,然后每次都从对角线下移,一直到越界或者matrix[i][j]已经在res里面。这里每次都要记录start_i, start_j,即左上角点,以及end_i, end_j右下角点。
Leetcode 题目解析之 Spiral Matrix II Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order. For example, Given n = 3, You should return the following matrix: [ 1, 2, 3 , 8, 9, 4 ,
https://leetcode.com/problems/spiral-matrix-ii/ 对于Spiral Matrix II, 这里我们只需要首先建立一个n*n的matrix,然后像I一样遍历即可。 上code class Solution(object): def generateMatrix(self, n): """ :type n: int :rtype: List[List[int]] ...
【摘要】 Leetcode 题目解析之 Spiral Matrix Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order. For example, Given the following matrix: [ 1, 2, 3 , 4, 5, 6 , 7, 8, 9 ...
Can you solve this real interview question? Spiral Matrix - Given an m x n matrix, return all elements of the matrix in spiral order. Example 1: [https://assets.leetcode.com/uploads/2020/11/13/spiral1.jpg] Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order. For example,Given n = 3, You should return the following matrix: [ [ 1, 2, 3 ], [ 8, 9, 4 ], [ 7, 6, 5 ] ] 题目标签:Array 这道题目和之前的螺旋矩阵几乎没有区别,而且更...