Main=Solution() Main.sortedArrayToBST(num1) 验证结果: Runtime:72 ms, faster than24.34%ofPython3online submissions forConvert Sorted Array to Binary Search Tree. Memory Usage:15.4 MB, less than5.70%ofPython3online submissions forConvert Sorted Array to Binary Search Tree. 速度太慢了,看来本题优...
Given an integer arraynumswhere the elements are sorted inascending order, convertit to aheight-balancedbinary search tree. Example 1: Input:nums = [-10,-3,0,5,9]Output:[0,-3,9,-10,null,5]Explanation:[0,-10,5,null,-3,null,9] is also accepted: Example 2: Input:nums = [1,3]...
LeetCode:Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST 分析:找到数组的中间数据作为根节点,小于中间数据的数组来构造作为左子树,大于中间数据的数组来构造右子树,递归解法如下 1/**2* Definition for binary tr...
Binary Tree Preorder Traversal 63 -- 4:35 App Leetcode-0101. Symmetric Tree 7 -- 1:29 App Leetcode-0167. Two Sum II - Input Array Is Sorted 12 -- 5:37 App Leetcode-0033. Search in Rotated Sorted Array 5 -- 2:23 App Leetcode-0026. Remove Duplicates from Sorted Array ...
题目链接:https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/ 题目: Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 思路: 新建一个结点保存mid值,该结点的左右子树也递归生成,这是个常用的模板 ...
Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 解题思路: 题意为构建有序数组的二分查找树。 比較简单。用递归方法就可以,中间的元素作为根节点,前半部分作为左孩子树,右半部分作为右孩子树。
总结: sorted array -> balanced bst ** Anyway, Good luck, Richardo! My code: /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } ...
* Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */publicclassSolution{public TreeNodesortedListToBST(ListNode head){if(head==null)returnnull;int total=1;ListNode temp=head;while(tem...
Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 本题是二分法的高级应用,每次选择root都是从数列的中间选择,那么最后构造出来的二叉树一定是高度平衡的BST了。
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1. ...