Sort a linked list in O(n log n) time using constant space complexity. 2.翻译 1 在固定的空间复杂度中使用O(nlog n)的时间复杂度进行链表的排序。 3.思路分析 提起排序,我们脑海中会迅速出现各种排序算法:冒泡排序、快速排序、简单排序、堆排序、直接插入排序、希尔排序(递减增量排序)、直接选择排
java代码如下: 1/**2* Definition for singly-linked list.3* class ListNode {4* int val;5* ListNode next;6* ListNode(int x) {7* val = x;8* next = null;9* }10* }11*/12publicclassSolution {13publicListNode sortList(ListNode head) {14quickSort(head,null);15returnhead;1617}18public...
https://leetcode.com/problems/insertion-sort-list/ 题目: Sort a linked list using insertion sort. 思路: 头插法。用头结点可以简化插入链表时候的操作,因为要考虑插入链表中间和表头两种情况,插入表头时,head就要更新,还要判断pre指针是否为空 算法: public ListNode insertSortList(ListNode head, ListNode t)...
题目:Sort a linked list using insertion sort. 即使用插入排序对链表进行排序。 思路分析: 插入排序思想见《排序(一):直接插入排序 》 C++参考代码: /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} ...
Leetcode-Sort List Description Sort a linked list in O(n log n) time using constant space complexity. Explain 看题目要求,第一个是链表,第二个是时间复杂度为O(n log n),空间复杂度为O (1)。排序算法中说到这个时间复杂度的话,肯定也就会想到快排和归并排序。归并排序如果用数组实现的话,是做不到...
-- 题目大意:对一个链表排序,时间复杂度:O(NlogN) ,空间复杂度:O(1) 题目: Sort a linked list in O(n log n) time using constant space complexity. Example 1: Input: 4->2->1->3 Output: 1->2->3->4 Example 2: Input: -1->5->3->4->0 ...
Leetcode:148_Sort List | O(nlogn)链表排序 | Medium 简介:题目:Sort List Sort a linked list in O(n log n) time using constant space complexity 看题目有两个要求:1)时间复杂度为O(nlogn);2)空间复杂度为常数,即不能增设额外的空间。
:pencil2: 算法相关知识储备 LeetCode with Python :books:. Contribute to visonpon/leetCode development by creating an account on GitHub.
Circular-linked list: linked list in which each node points to the next node and the last node points back to the first node Time Complexity: Access:O(n) Search:O(n) Insert:O(1) Remove:O(1) Stack AStackis a collection of elements, with two principle operations:push, which adds to ...
[LeetCode]148. Sort List 2019-12-11 21:14 −```c++ /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; ... HZQTS 0 209 zzq's sort [思维题] ...