Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input:1->2->4, 1->3->4Output:1->1->2->3->4->4 因为没有空间要求,所以想
Output: 1->1->2->3->4->4 这个题目思路就是用dummy node,然后依次判断是l1 小还是l2小,最后当一方是None的时候将另一方加在总list的最后即可。 Code classListNode:def__init__(self, x): self.val=x self.next=NoneclassSolution:defmergeTwoLists(self, l1, l2): dummy=ListNode(0) head=dummywh...
//leetcode.cn/problems/middle-of-the-linked-list/ """ class Solution1: def mergeTwoLists(self, list1: Optional[ListNode], list2: Optional[ListNode]) -> Optional[ListNode]: # 迭代法 dummy = cur = ListNode(0) while list1 and list2: # 当有为空的时候可以停止了把剩下的接上去就行。
我的github连接:https://github.com/princewen/leetcode_python 21. Merge Two Sorted Lists Merge Two Sorted Lists 很简单的链表拼接题,但是要注意两个地方 1、返回值要返回head.next 2、无需判断循环后哪个不为空,or返回第一个为真的值 # Definition for singly-linked list. # class ListNode(object): #...
最近有朋友问我怎么没有更新文章了,因为最近有空的时候都在刷 LeetCode,零零星星刷了快 2 个月了,也累积了不少题目了,所以最近打算把做的几百道题归类,总结一下。所有题目的代码在github.com/halfrost/Le…,每道题都有测试用例和测试代码。 Linked List 的 Tips: ...
LeetCode之Linked List题目汇总 Add Two Numbers Convert Sorted List to Binary Search Tree Delete Node in a Linked List Insertion Sort List Intersection of Two Linked Lists Linked List Cycle Linked List Cycle II Merge Two Sorted Lists Palindrome Linked List ...
Leetcode 92题反转链表 II(Reverse Linked List II) 题目链接 https://leetcode-cn.com/problems/reverse-linked-list-ii/ 题目描述 反转从位置 m 到 n 的链表。请使用一趟扫描完成反转。 说明: 1 ≤ m ≤ n ≤ 链表长度。 示例: 输入: 1->2->3->4->5->NULL, m = 2, n = 4 输出: 1->4...
Can you solve this real interview question? Reverse Linked List - Given the head of a singly linked list, reverse the list, and return the reversed list. Example 1: [https://assets.leetcode.com/uploads/2021/02/19/rev1ex1.jpg] Input: head = [1,2,3,
输入:intersectVal = 2, listA = [0,9,1,2,4], listB = [3,2,4], skipA = 3, skipB = 1输出:Intersected at '2'解释:相交节点的值为 2 (注意,如果两个链表相交则不能为 0)。 从各自的表头开始算起,链表 A 为 [0,9,1,2,4],链表 B 为 [3,2,4]。在 A 中,相交节点前有 3 个...
list. The new node should be inserted between node 1 and node 3. After the insertion, the list should look like this, and we should still return node 3. 1. 2. 3. 4. 5. 6. Example 2: Input: head = [], insertVal = 1