//compare参数实现,匿名函数lambda,这种比较方法的可行性ASCII码的比较,0对应dec的48 in ASCII中美国标准信息交换代码ANSI制定 string res; for(auto s:arr) res+=s; while(res[0]=='0' && res.length()>1) res.erase(0,1); /*erase函数的原型如下: (1)str
GITHUB: https://github.com/yuzhangcmu/LeetCode_algorithm/blob/master/list/SortList.java
publicclassSort{publicstaticvoidmain(String[]args){int[]unsortedArray=newint[]{6,5,3,1,8,7,2,4};bubbleSort(unsortedArray);System.out.println("After sort: ");for(intitem:unsortedArray){System.out.print(item+" ");}}publicstaticvoidbubbleSort(int[]nums){intlen=nums.length;for(inti=0;...
Given a strings, sort it in decreasing order based on the frequency of characters, and returnthe sorted string. Example 1: Input: s = "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Therefore...
LeetCode: Sort List 解题报告 Sort List Sort a linked list in O(n log n) time using constant space complexity. 使用Merge Sort, 空间复杂度是 O(logN) 因为使用了栈空间。 SOLUTION 1: 使用Merge Sort来解决问题。 为什么不用QuickSort? 因为随机访问对于链表而言太耗时,而heap sort不可行。
You are not suppose to use the library's sort function for this problem. click to show follow up. Follow up: A rather straight forward solution is a two-pass algorithm using counting sort. First, iterate the array counting number of 0's, 1's, and 2's, then overwrite array with total...
Yu's garden Sort Colors Given an array with n objects colored red, white or blue, sort them so that objects of the same color are adjacent, with the colors in the order red, white and blue. Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue...