最直接的思路是对每一个元素尝试查找是否有重,如果没有重,就返回。 java代码如下: publicclassSolution {publicintsingleNumber(int[] nums) {inti=0;intj=0;intn=nums.length;for(i=0;i<n;i++){for(j=0;j<n;j++){if(i==j)continue;elseif(nums[i]==nums
classSolution {publicintsingleNumber(int[] nums) {intres = 0;for(intnum : nums) res ^=num;returnres; } } 类似题目: Single Number III Single Number II Missing Number Find the Difference Find the Duplicate Number 参考资料: https://leetcode.com/problems/single-number/ https://leetcode.com...
136. Single Numberwindliang 互联网行业 开发工程师 来自专栏 · LeetCode刷题 题目描述(简单难度) 所有数字都是成对出现的,只有一个数字是落单的,找出这个落单的数字。 解法一 题目要求线性复杂度内实现,并且要求没有额外空间。首先我们考虑假如没有空间复杂度的限制。 这其实就只需要统计每个数字出现...
var singleNumber = function(nums) { return nums.reduce((res,a)=>res^a,0); }; 参考资料 LeetCode- Bit Manipulation LeetCode总结(1) —— 位运算:blog.csdn.net/xsloop/ar blog.csdn.net/zhning12L 欢迎加入码蜂社算法交流群:天天一道算法题 扫描下方二维码或搜素“码蜂社”公众号,不怕错过好文章...
Actually this algorithm can be extended to three times, four times, five times etc.. importjava.util.*;publicclassSolution{publicintsingleNumber(int[]A){int[]zero=newint[32];int[]one=newint[32];for(inti=0;i<A.length;i++){for(intj=0;j<32;j++){if(((1<<j)&A[i])!=0){one...
【leetcode】数组中找出只出现一次的数字(Single Number),题目是这样说的:Givenanarrayofintegers,everyelementappears twice exceptforone.Findthatsingleone.Note:Youralgorithmshouldhavealinearruntimecomplexity.Couldyouimplementitwit
leetcode 算法解析(一):260. Single Number III 260.Single Number II 原题链接 本题其实算是比较简单,在 leetcode 上也只是 medium 级别,ac 率也很高,最好先自己尝试,本文只是单纯的记录一下自己整体的思路; 在阅读本文章之前,最好先解锁本题的简单模式136.Single Number,这对理解本题有较大的帮助;...
Leetcode 137 Single Number II Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
//方法一:Hash Table(HashMap) class Solution { public int singleNumber(int[] nums) { if(nums.length==0||nums==null){ return 0; } HashMap<Integer , Integer> map = new HashMap<Integer , Integer>(); for(int i=0;i<nums.length;i++){ if(!map.containsKey(nums[i])){ map.put(nu...
Hello. Today I removed the accountzh0ukangyangfrom the rating, after first nullifying its results in the Pinely Round 3 (Div. 1 + Div. 2) and banning it. I would like to remind you again: Codeforces insists on the policy of using a single account. Creating and using additional accounts...