当我们更新了三角函数的定义方式后,自然就会遇到三种函数的值的相互关系,比如已知$\sin\theta+\cos\theta$[四则运算之一,加法]的值,如何求解关于$\sin\theta$和$\cos\theta$之间的四则运算的剩余运算[减法、乘法、除法],是本博文探讨的重点。
求三角函数值 sin(theta)=1/2 , cos(theta) sin(θ)=12sin(θ)=12,cos(θ)cos(θ) 使用正弦的定义求单位圆直角三角形的已知边。象限将决定每一个值的符号。 sin(θ)=对边斜边sin(θ)=对边斜边 求单位圆三角形的邻边。由于斜边和对边已知,使用勾股定理即可求最后一条边。
Find the exact value of sec(\theta). Find the exact value of cos(\theta) given tan(\theta) = \frac{5}{12} \; \rm and \; sin(\theta) < 0. Find the exact value of sin(\theta) given tan(\theta) = \frac{5}{12} \; \rm and \; sin(\theta) < 0. ...
Answer to: Find the values of \sin \theta, \cos \theta, and \tan \theta for the given right triangle. By signing up, you'll get thousands of...
in degrees cos(theta)=sin(theta) cos ( θ ) = sin ( θ ) cos ( θ ) = sin ( θ ) divide each term in the equation by cos ( θ ) cos ( θ ) . cos ( θ ) cos ( θ ) = sin ( θ ) cos ( θ ) cos ( θ ) cos ( θ ) = sin ( θ ) cos ( θ ) cancel ...
\sin \theta +\cos \theta =\dfrac{1}{5}\Rightarrow 1+2\sin \theta \cos \theta =\dfrac{1}{25}\Rightarrow 2\sin \theta \cos \theta =-\dfrac{24}{25} < 0∵\theta \in (0, \pi ),∴\sin \theta >0,∴\cos \theta < 0,∴\sin \theta -\cos \theta >0,{{\left( \...
若\cos \theta \lt 0,且\cos \theta -\sin \theta = \sqrt{1-\sin 2\theta },那么\theta 是( )A
1 Answers Arun 25750 Points 4 years ago Dear Kaushal cos theta cos alpha - sin theta sin alpha = cos ( theta + alpha) Hope it helps In case of any difficulty, please feel free to ask again Approved Other Related Questions on Trigonometry...
要求:已知一个角度theta,求cos(theta)和sin(theta) 解决办法:把一个(x,y)=(常量K_fxp,0)的初始向量,即此向量和X轴的夹角为0,不断的旋转N次,直到和X轴的夹角无限接近theta为止,此时的(xn,yn)就是cos和sin的值, 常量K_fxp的取值来源于每次旋转后向量的幅值会发生变化,提前已知迭代(旋转)的次数,那么这个...
(2)由$\left ( {1} \right )$得$sin\theta cos\theta =\dfrac {12} {25}$$\gt 0$, $\therefore $$0\lt \theta \lt \dfrac {\pi } {2}$, 解$sin\theta -cos\theta =\dfrac {1} {5}$,$sin\theta cos\theta =\dfrac {12} {25}$, 得$sin\theta =\dfrac {4} {5}$,...