首先，我们将sinθcosθ进行转换，利用三角函数的和差化积公式，将其转化为：$sintheta costheta = sqrt{2}left$进一步地，我们可以将其看作是两个特殊角度的正弦和余弦值的乘积，即：$sqrt{2}left$利用正弦的两角和差公式，上式可以化简为：$sqrt{2}sinleft$求最大值：接下来，我们需要找到$s...
\displaystyle sin\theta+sin\phi=2sin(\frac{\theta+\phi}{2})\cdot cos(\frac{\theta-\phi}{2}) ⑵.公式3-②推导 根据前面的公式1-③、1-④。 cos(α+β)=cosα·cosβ-sinα·sinβ···1-③ cos(α-β)=cosα·cosβ+sinα·sinβ···1-④ 二式相加,得 cos(α+β)+cos(α-β...
Step by step video & image solution for |[sin theta, tan theta, sec theta] , [cos theta, cot theta, cosec theta] , [1,2,3]|= by Maths experts to help you in doubts & scoring excellent marks in Class 11 exams.Updated on:21/07/2023Class...
≠ View Solution Finddydx, whenx=a(cosθ+θsinθ)andy=a(sinθ−θcosθ) View Solution Ifx=a(cosθ+logtan(θ2))andy=asinθthen finddydxatθ=π3andθ=π4 View Solution Doubtnut is No.1 Study App and Learning App with Instant Video Solutions for NCERT Class 6, Class 7, Class 8...
1, 1]$。图形判断：方程$y^2 = 1 + x$表示的是一个抛物线的一部分，具体来说，是抛物线$y^2 = 1 + x$在区间$[1, 1]$上的部分。因此，方程$x = sintheta$ 和 $y = sinfrac{theta}{2} + cosfrac{theta}{2}$所表示的图形是抛物线$y^2 = 1 + x$的一部分。
【题目】已知$$ \sin \theta + \cos \theta = \frac { 1 } { 5 } $$,求sinθ、cosθ、tanθ的值.
Answer to: Find the derivative of h(theta) = sin theta/sin theta + cos theta. By signing up, you'll get thousands of step-by-step solutions to your...
Answer to: Find f. f double prime (theta) = sin theta + cos theta, f(0) = 4, f prime (0) = 4. By signing up, you'll get thousands of step-by-step...
【解析】 解:由题意得$$\left\{ \begin{matrix} \tan \theta = 2 , \\ \sin ^ { 2 } \theta + \cos ^ { 2 } \theta = 1 \end{matrix} \right.$$ 即$$\left\{ \begin{matrix} \frac { \sin \theta } { \cos \theta } = 2 , \\ \sin ^ { 2 } \theta + \cos ^ { 2...
Find the value of theta, which satisfy 3-2 cos theta-4 sintheta-cos 2theta + sin 2theta=0.