Establish the identity. {eq}\displaystyle\dfrac {\sin \theta - \cos \theta} {\cos \theta} + \dfrac {\sin \theta + \cos \theta} {\sin \theta} = \csc \theta \sec \theta {/eq} Establishing Trigonometric Identity Trigonometric identity ...
Answer to: Prove the identity. sin theta cot theta = cos theta. By signing up, you'll get thousands of step-by-step solutions to your homework...
( (1+(sin)(θ )+(cos)(θ ))/(1+(sin)(θ )-(cos)(θ ))=(1+(cos)(θ ))/((sin)(θ ))) 相关知识点: 试题来源: 解析 The provided equation is an identity but there are no steps available. ( (1+(sin)(θ )+(cos)(θ ))/(1+(sin)(θ )-(cos)(θ ))=(1+(cos)(...
sin^(2)theta+cos^(2)theta=1 Squaring both sides sin^(4)theta+cos^(4)theta =1-2 sin^(2)theta.cos^(2)theta Put theta= 90^(@) =1-2sin^(2)90^(@).cos^(2)90^(@)=1-0=1
If u =-f''(theta) sintheta + f'(theta) costheta and v = f''(theta) costheta + f'(theta) sintheta , then int[((du)/(d theta))^2+((dv)/(d theta))^2]^(1/2)d theta is equal to View Solution If∫sinθ−cosθ(sinθ+cosθ)√sinθcosθ+sin2θcos2θdθ=cosec_1(...
Complete the quotient identity. ?=sinθcosθ =sinθcosθThere are 2 steps to solve this one. Solution Share Step 1 View the full answer Step 2 Unlock Answer UnlockPrevious question Next questionNot the question you’re looking for? Post any question and get ex...
若\sin\theta\cos\theta=\dfrac{12}{25},且\theta\in(0,\dfrac{\pi}{4}),则\sin\theta-\cos\th
化简sin(theta)*cos(theta)*csc(theta) sin(θ)⋅cos(θ)⋅csc(θ)sin(θ)⋅cos(θ)⋅csc(θ) 将csc(θ)(θ)重写为正弦和余弦形式。 sin(θ)cos(θ)⋅1sin(θ)sin(θ)cos(θ)⋅1sin(θ) 约去sin(θ)sin(θ)的公因数。
Identify the Polar Equation r=1/(cos(theta)+5sin(theta))( r=1/((cos)(θ )+5(sin)(θ )))
The trigonometric angle identity sin(α+β)=sinαcosβ+cosαsinβsin(α+β)=sinαcosβ+cosαsinβ is exactly what you need. Note that A2+B2=C2A2+B2=C2, or (A/C)2+(B/C)2=1.(A/C)2+(B/C)2=1. Thus there exists an angle ϕϕ such that c...