s = Styler(self.df, precision=2) self.assertEqual(s.precision,2) s2 = s.set_precision(4) self.assertTrue(siss2) self.assertEqual(s.precision,4) pandas.io.formats.style.Styler.set_precision方法示例由纯净天空License
Styler.set_properties(subset=None, **kwargs)将定义的CSS-properties 设置为给定子集中的每个 HTML 元素。参数: subset:标签,array-like,IndexSlice,可选 DataFrame.loc[<subset>] 的有效 2d 输入,或者在 1d 输入或单键的情况下,到列优先的 DataFrame.loc[:, <subset>],在应用函数之前将 data 限制为。 *...
I was using the Styler.set_properties() function to format the Pandas Dataframe, while it (df_style) shows up nicely in Jupyter Notebook, it caused an error in the Styler.to_excel() function. Could you please advise how I can fix it? [Issue also posted in stackoverflow.com: https:/...
pandas: 2.0.1 scikit-learn: 1.2.2 torch: 1.9.0+cu111 trained_for_benchmark: false trained_for_benchmark: true training_set: title: MPTrj url: https://figshare.com/articles/dataset/19470599 size: 1_580_395 # hyperparams: see align-config.json 5 changes: 5 additions & 0 deletions 5...
可与Styler.set_table_styles 结合使用以定义内部 CSS 解决方案,而无需参考外部 CSS 文件。 例子: >>> df = pd.DataFrame(data=[[1, 2, 3], [4, 5, 6]], columns=["A", "B", "C"]) >>> classes = pd.DataFrame([ ... ["min-val red", "", "blue"], ... ["red", None, ...