百度试题 题目 按各科成绩进行排序,并显示排名,Score 重复时保留名次空缺SELECT *, RANK() OVER(PARTITION BY sc.cid ORDER BY sc.score DESC)排名FROM sc; A.正确B.错误 相关知识点: 试题来源: 解析 A 反馈 收藏
select dense_rank() over(partition by f_deptid order by f_salary desc) as f_order, f_deptname, f_employeename, f_salary from (select a.f_employeeid, a.f_deptid, b.f_deptname, a.f_employeename, a.f_salary from t_employee a, t_dept b where a.f_deptid = b.f_deptid) t; ...
select rank() over (partition by deptno order by sal desc) rank, e.* from emp e ) where rank rank 函数的作用是产生排名,与普通函数不同,高亮部分都是函数语法部分,其中over 是 关键字,总体意思是指按部门编号分组(partition by deptno),按工资降序(order by sal desc) 排名。 思路3: 步骤1:按照...
select * from (select rank() over(partition by barcode order by sheetdate) num, * from ScanRecord where scanMode=0 and workStageName='QC')t where num=1
Describe the problem Please describe the issue you observed, and any steps we can take to reproduce it: SQL *SELECT ,rank() OVER(PARTITION BY i ORDER BY j desc) AS r FROM t1; returns the wrong results. To Reproduce What did you do? Descr...
-- 必须用DENSE_RANK() SELECT uid, exam1 AS exam_complete_cnt FROM ( SELECT uid, COUNT(exam_id) AS exam1, COUNT(score) AS exam2 FROM ( SELECT *, DENSE_RANK() OVER(PARTITION BY uid ORDER BY DATE_FORMAT(start_time, '%Y%m') DESC) AS month_rank FROM exam_record ) tab WHERE mont...
按各科成绩进行排序,并显示排名,Score 重复时保留名次空缺SELECT *, RANK() OVER(PARTITION BY sc.cid ORDER BY sc.score DESC)排名FROM sc;A.正确B.错误的答案是什么.用刷刷题APP,拍照搜索答疑.刷刷题(shuashuati.com)是专业的大学职业搜题找答案,刷题练习的工具.一键将
connect by prior mgr = empno; 17、排序函数 --按部门分组,给出分组后的序号 select row_number() over(partition by deptno order by sal), emp.* from emp; --rank排序,空出相同部分 select rank() over(partition by deptno order by sal), emp.* from emp; ...
connectbypriormgr = empno; 17、排序函数 --按部门分组,给出分组后的序号 selectrow_number()over(partitionbydeptnoorderbysal), emp.*fromemp; --rank排序,空出相同部分 selectrank()over(partitionbydeptnoorderbysal), emp.*fromemp; selectrank()over(orderbydeptno), emp.*fromemp; ...
connectbypriormgr = empno; 17、排序函数 --按部门分组,给出分组后的序号 selectrow_number()over(partitionbydeptnoorderbysal), emp.*fromemp; --rank排序,空出相同部分 selectrank()over(partitionbydeptnoorderbysal), emp.*fromemp; selectrank()over(orderbydeptno), emp.*fromemp; ...