Given the root node of a binary search tree (BST) and a value. You need to find the node in the BST that the node's value equals the given value. Return the subtree rooted with that node. If such node doesn't exist, you should return NULL. For example, Given the tree: 4 / \ ...
Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST. According to thedefinition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (wh...
Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST.According to the definition of LCA on Wikipedia:“The lowest common ancestor is defined between two nodes p and q as the lowest node in T that has both p and q as descendants (wher...
Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST. According to thedefinition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (wh...
image.png For example, the lowest common ancestor (LCA) of nodes 2 and 8 is 6. Another example is LCA of nodes 2 and 4 is 2, since a node can be a descendant of itself according to the LCA definition. 大意: 给出一个二叉查找树(BST),在其中找到给出的两个节点的最低的共同祖先(LCA...
The number of nodes in the tree is in the range[2, 105]. -109 <= Node.val <= 109 AllNode.valare unique. p != q pandqwill exist in the BST. 二叉搜索树的最小公共祖先。 影子题236。题意是给一个二叉搜索树(BST)和两个节点p和q,请找出两个节点的最小公共祖先。思路是递归,因为BST的...
add_bst(root) def next(self) -> int: # 取出栈顶结点 top , top 就是下一个需要遍历的结点 top: TreeNode = self.stack.pop() #将 top 的左子树放入栈中 self.add_bst(top.right) # 返回 top 的值 return top.val def hasNext(self) -> bool: # 如果栈不为空,则还有下一个结点 return ...
今天介绍的是LeetCode算法题中Easy级别的第163题(顺位题号是700)。给定一个二叉搜索树(BST)的和正整数val。 你需要在BST中找到节点的值等于给定val的节点。返回以该节点为根的子树。如果此节点不存在,则应返回null。例如: 鉴于树: 4 / \ 2 7 / \ 1 3 ...
总结: inorder BST 出来的数列是从小到大排列的。 构造函数中可以使用 return ** Anyway, Good luck, Richardo! My code: /** * Definition for binary tree * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } ...
Leetcode 34. Find First and Last Position of Element in Sorted Array 在一个有序数组中找到第一个和最后一个元素 解决思路: 利用二分法来进行位置的查找,主要涉及两个函数intlower_bound(nums, target)和intupper_bound(nums, target); 分别找到target的第一个和最后一个位置。 其中主要有一下几个方面需要...