Given the root node of a binary search tree (BST) and a value. You need to find the node in the BST that the node's value equals the given value. Return the subtree rooted with that node. If such node doesn't exist, you should return NULL. For example, Given the tree: 4 / \ ...
给定二叉搜索树(BST)的根节点和一个值。 你需要在BST中找到节点值等于给定值的节点。 返回以该节点为根的子树。 如果节点不存在,则返回 NULL。 classSolution{public: TreeNode* searchBST(TreeNode* root, intval) {if(root == NULL)returnNULL;if(root ->val==val)returnroot;elseif(root ->val>val)re...
来自专栏 · Leetcode刷题笔记 1 人赞同了该文章 题目描述 英文版描述 Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST.According to the definition of LCA on Wikipedia:“The lowest common ancestor is defined between two nodes p and q as...
Left } } /** * Your BSTIterator object will be instantiated and called as such: * obj := Constructor(root); * param_1 := obj.Next(); * param_2 := obj.HasNext(); */ 题目链接: Binary Search Tree Iterator : leetcode.com/problems/b 二叉搜索树迭代器: leetcode-cn.com/problem ...
LeetCode-Insert into a Binary Search Tree Description: Given the root node of a binary search tree (BST) and a value to be inserted into the tree, insert the value into the BST. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist ...
leetcode 501. Find Mode in Binary Search Tree Given a binary search tree (BST) with duplicates, find all themode(s)(the most frequently occurred element) in the given BST. Assume a BST is defined as follows: The left subtree of a node contains only nodes with keysless than or equal ...
LeetCode 每日一题 Daily Challenge 107 Binary Tree Level Order Traversal II 369 -- 4:05 App LeetCode 每日一题 Daily Challenge 239 Sliding Window Maximum 113 1 2:43 App LeetCode 每日一题 Daily Challenge 538 Convert BST to Greater Tree 237 -- 5:28 App LeetCode 每日一题 Daily Challenge 79...
今天介绍的是LeetCode算法题中Easy级别的第163题(顺位题号是700)。给定一个二叉搜索树(BST)的和正整数val。 你需要在BST中找到节点的值等于给定val的节点。返回以该节点为根的子树。如果此节点不存在,则应返回null。例如: 鉴于树: 4 / \ 2 7 / \ 1 3 ...
总结: inorder BST 出来的数列是从小到大排列的。 构造函数中可以使用 return ** Anyway, Good luck, Richardo! My code: /** * Definition for binary tree * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } ...
Leetcode 34. Find First and Last Position of Element in Sorted Array 在一个有序数组中找到第一个和最后一个元素 解决思路: 利用二分法来进行位置的查找,主要涉及两个函数intlower_bound(nums, target)和intupper_bound(nums, target); 分别找到target的第一个和最后一个位置。 其中主要有一下几个方面需要...