class Solution: def searchInsert(self, nums: List[int], target: int) -> int: # 二分区间的左边界,初始化为 0 l: int = 0 # 二分区间的右边界,初始化为 len(nums) - 1 r: int = len(nums) - 1 # 当区间不为空时,继续二分 # (注意这里取等号是因为我们的区间是左闭右闭区间, # 且...
classSolution {publicintsearchInsert(int[] nums,inttarget) {inti = 0;intj = nums.length - 1;intindex = -1;while(j - i > 5) {intmid = (i + j) / 2;if(nums[mid] >target) { j=mid; }elseif(nums[mid] <target) { i=mid; }else{ index=mid;break; } }for(intk = i; k ...
LeetCode---35. Search Insert Position 【Leetcode】35. Search Insert Position ARTS leetcode9 Search Insert Position [LeetCode]35. Search Insert Position 35. Search Insert Position 35. Search Insert Position 查找位置 Search Insert Position LeetCode刷题之路(35)—— Search Insert Position LeetCode编...
来自专栏 · Leetcode每日一题array篇 题目要点 input: nums->list[int], target->int output: int, the (inserted) index of target O(logn) running time 代码 class Solution: def searchInsert(self, nums: List[int], target: int) -> int: l=0 r=len(nums)-1 while(l<=r): mid = (l+...
今天分享leetcode第7篇文章,也是leetcode第35题—Search Insert Position,地址是:https://leetcode.com/problems/search-insert-position/ 重磅干货:本篇文章将在解题基础上分享二分查找变形的解法 【英文题目】(学习英语的同时,更能理解题意哟~) Given a sorted array and a target value, return the index if...
LeetCode 35: Search Insert Position 标签:数组,简易 问题描述 Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in......
Leetcode力扣 1-300题视频讲解合集|手画图解版+代码【持续更新ing】 33.9万 585 视频 爱学习的饲养员 常规法 Python3版本 Java版本 二分法 Python3版本 Java版本本文为我原创本文禁止转载或摘编 计算机 程序员 编程 Python Java Leetcode 力扣 分享到: 投诉或建议 ...
publicclassSolution {publicintSearchInsert(int[] nums,inttarget) {if(nums.Length ==0)return0;intindex =0;while(nums[index] <target){ index++;if(index ==nums.Length)break; }returnindex; } } 开始渐渐习惯了LeetCode的题目描述和解题规范。继续加油...
搜索插入位置(search-insert-position)(二分)[简单] 链接https://leetcode-cn.com/problems/search-insert-position/ 耗时 解题:17 min 题解:3 min 题意 给定一个排序数组和一个目标值,在数组中找到目标值,并返回其索引。如果目标值不存在于数组中,返回它将会被按顺序插入的位置。 你可以假设数组中无重复...
class Solution: def searchInsert(self, nums, target): """ :type nums: List[int] :type target: int :rtype: int """ for i in range(len(nums)): if target == nums[i]: print(i) return i # 直接跳出for循环,说明target不存在于nums中 if target > nums[i]: print(i+1) return i+...