You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplicate exists in the array. packagecom.leetcode.SearchInRotatedSortedArray;/*** (1)如果ta
Can you solve this real interview question? Search in Rotated Sorted Array - There is an integer array nums sorted in ascending order (with distinct values). Prior to being passed to your function, nums is possibly rotated at an unknown pivot index k (1
Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplicate exists in the ...
leetCode 33. Search in Rotated Sorted Array(c语言版本) bingo酱 I am a fighter 来自专栏 · leetcode每日斩 题目大意: 给定一个旋转升序的数组,所谓旋转就是假设把头和尾连接起来,然后找到最小那个数开始,往后开始就是升序的,直到再回到最小那个数为止。这样看起来就像一个环一样。 然后,现在给定一个数,...
题目链接:https://leetcode.com/problems/search-in-rotated-sorted-array/题目: Suppose a sorted array is rotated at some pivot unknown to you beforehand. 0 1 2 4 5 6 7might become4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, ...
Search in Rotated Sorted Array I && II Leetcode 对有序数组进行二分查找(下面仅以非递减数组为例): 1. int binarySort(int A[], int lo, int hi, int target) 2. { 3. while(lo <= hi) 4. { 5. int mid = lo + (hi - lo)/2; ...
[ 4 5 6 7 1 2 3] ,如果 target = 2,那么数组可以看做 [ -inf -inf - inf -inf 1 2 3]。 和解法一一样,我们每次只关心 mid 的值,所以 mid 要么就是 nums [ mid ],要么就是 inf 或者 -inf。 什么时候是 nums [ mid ] 呢?
小范的leetcode日记(33)Search in Rotated Sorted Array, 视频播放量 16、弹幕量 0、点赞数 1、投硬币枚数 0、收藏人数 1、转发人数 0, 视频作者 小范刷题, 作者简介 ,相关视频:小范的leetcode日记(81)Search in Rotated Sorted Array II,小范的leetcode日记(80)Remove D
LeetCode-33-搜索旋转排序数组(Search in Rotated Sorted Array)33. 搜索旋转排序数组整数数组 nums 按升序排列,数组中的值 互不相同。在传递给函数之前,nums 在预先未知的某个下标 k(0 <= k < nums.length)上进行了 旋转,使数组变为 [nums[k], nums[k+1], ..., nums[n-1], nums[0], nums[1...
因为 (位置 + 偏移)% n = 数组下标,即 (n - 1 + 偏移)% n = start,n - 1 加偏移超过了 n,所以取模理解成减 n 。 有了偏移,我们就可以愉快的找目标值的数组下标了。 publicintsearch(int[]nums,inttarget){intstart=0;intend=nums.length-1;//找出最小值的数组下标/* while (start < end)...