81. Search in Rotated Sorted Array II There is an integer arraynumssorted in non-decreasing order (not necessarily withdistinctvalues). Before being passed to your function,numsisrotatedat an unknown pivot indexk(0 <= k < nums.length) such that the resulting array is[nums[k], nums[k+1...
如果我们不用这种方法,那么我们需要更加深入地去判断每种可能出现地情况。 当nums[mid] > nums[start] 和 nums[mid] < nums[end] 都不满足时,则: numd[start] <= nums[mid] 并且 nums[mid] >= nums[end] 如果我们再仔细想,由于数组旋转之前整体有序,那么旋转之后得到的两条线段本身应该是有序的,而且...
此题是Search in Rotated Sorted Array的加强版,将一个有序数组往右移动若干位。这里的有序数组允许有重复数字。 如果没有重复数字,那么复杂度是O(logn),用二分查找,根据中间值和左右两边的大小,以及和target的大小,来判断缩小一半查找。 但是出现重复数字之后,如果中间值和左右两边的值相等,我们就不知道如何切除...
题目链接:https://leetcode.com/problems/search-in-rotated-sorted-array-ii/ 题目: Follow up for “Search in Rotated Sorted Array”: What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. ...
Write a function to determine if a given target is in the array. The array may contain duplicates. 这道题很简单,直接遍历即可。也可以使用二分查找。 代码如下: public class Solution { /* * 最简单的就是遍历 * */ public boolean search(int[] nums, int target) ...
leetCode 33. Search in Rotated Sorted Array(c语言版本) bingo酱 I am a fighter 来自专栏 · leetcode每日斩 题目大意: 给定一个旋转升序的数组,所谓旋转就是假设把头和尾连接起来,然后找到最小那个数开始,往后开始就是升序的,直到再回到最小那个数为止。这样看起来就像一个环一样。 然后,现在给定一个数,...
1. Description Search in Rotated Sorted Array II 2. Solution class Solution{public:boolsearch(vector<int>&nums,inttarget){intsize=nums.size();intleft=0;intright=size-1;while(left<=right){intmid=(left+right)/2;if(nums[mid]==target){returntrue;}if(nums[left]==nums[mid]){left++;cont...
题目链接 https://leetcode.com/problems/search-in-rotated-sorted-array-ii/ 解题思路 先找到数组被rotate...
今天的笔记包含基于改造二分法(Modified Binary Search)类型下的7个题目,它们在leetcode上的编号和题名分别是: 704 - 二分查找 74 - 搜索二维矩阵 33 - 搜索旋转排序数组 81 - 搜索旋转排序数组 II 153 - 寻找旋转排序数组中的最小值 162 - 寻找峰值 ...
81. Search in Rotated Sorted Array II Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,0,1,2,2,5,6] might become [2,5,6,0,0,1,2]). You are given a target value to search. If found in the array return true, ...