classSolution {publicintsearch(int[] nums,inttarget) {returnsearch(nums, 0, nums.length - 1, target); }privateintsearch(int[] nums,intlow,inthigh,inttarget) {if(low >high)return-1;intmid = (low + high) / 2;if(nums[mid] ==target)returnmid;if(nums[mid] <nums[high]) { //后...
Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e.,0 1 2 4 5 6 7might become4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplicate ...
publicintsearch(int[]nums,inttarget){intstart=0;intend=nums.length-1;//找出最小值的数组下标/* while (start < end) {int mid = (start + end) / 2;if (nums[mid] > nums[end]) {start = mid + 1 ;} else {end = mid;}}int bias = start;*///找出最大值的数组下标while(start<end...
题目 Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e.,[0,1,2,4,5,6,7]might become[4,5,6,7,0,1,2]). You are given a target value to search. If found in the array return its index, otherwise return-1. You may assume no ...
一、33. Search in Rotated Sorted Array Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e.,0124567might become4567012). You are given a target value to search. If found in the array return its index, otherwise return -1. ...
33. Search in Rotated Sorted Array 假设按照升序排序的数组在预先未知的某个点上进行了旋转。 ( 例如,数组 [0,1,2,4,5,6,7] 可能变为 [4,5,6,7,0,1,2] )。 搜索一个给定的目标值,如果数组中存在这个目标值,则返回它的索引,否则返回 -1 。
Search in Rotated Sorted Array 描述 Suppose a sorted array is rotated at some pivot unknown to you beforehand. 2.1 数组 5 (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return ...
target小于nums[0] && mid 大于 target也有两种情况 Runtime: 0 ms, faster than 100.00% of Java online submissions for Search Insert Position. \classSolution{publicintsearch(int[]nums,inttarget){intn=nums.length;if(n==0)return-1;intleft=0;intright=n-1;while(left+1<right){intmid=left+(...
33. Search in Rotated Sorted Array 题解 题目意思就是在一个上升序列中截断成AB 两个子序列 然后BA拼接成一个新的序列, 而题目要求 我们查找在这个序列中是否存在target,如果看到这里就会发现 这个很简单啊,查找一个序列中是否有某个数字 直接遍历就好了 方法木佬佬,但是 最重要的是题目末尾有一句 ...
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