Write a function to determine if a given target is in the array. 与Find Minimum in Rotated Sorted Array,Find Minimum in Rotated Sorted Array II,Search in Rotated Sorted Array对照看 解法一:顺序查找 classSolution {public:
一:Search in Sorted Array 二分查找,可有重复元素,返回target所在的位置,只需返回其中一个位置,代码中的查找范围为[low,high),左闭右开,否则容易照成死循环。 代码: classSolution {public:intsearch(vector<int>& nums,inttarget) {intnumsSize =nums.size();intlow =0,high =numsSize;while(low <high)...
Suppose a sorted array is rotated at some pivot unknown to you beforehand.(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).You are given a target value to search. If found in the array return its index, otherwise return -1.You may assume no duplicate exists in the array...
public class Solution { /** * @param A: an integer rotated sorted array * @param target: an integer to be searched * @return: an integer */ public int search(int[] A, int target) { if (A == null || A.length == 0) { return -1; } int left = 0; int right = A.length...
33. Search in Rotated Sorted Array 假设按照升序排序的数组在预先未知的某个点上进行了旋转。 ( 例如,数组 [0,1,2,4,5,6,7] 可能变为 [4,5,6,7,0,1,2] )。 搜索一个给定的目标值,如果数组中存在这个目标值,则返回它的索引,否则返回 -1 。
Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,0,1,2,2,5,6] might become [2,5,6,0,0,1,2]). You are given a target value to search. If found in the array return true, otherwise return false. Example 1: Input: num...
impl Solution { pub fn search(nums: Vec<i32>, target: i32) -> i32 { search_recursive(&nums, target).map_or(-1, |i| i as i32) } } fn search_recursive(nums: &[i32], target: i32) -> Option<usize> { let n = nums.len(); ...
1. Description Search in Rotated Sorted Array II 2. Solution class Solution{public:boolsearch(vector<int>&nums,inttarget){intsize=nums.size();intleft=0;intright=size-1;while(left<=right){intmid=(left+right)/2;if(nums[mid]==target){returntrue;}if(nums[left]==nums[mid]){left++;cont...
先找到数组被rotated的位置如果有的话。 确定好位置之后再在排序的数据区间内查找元素。 代码 class Solution{public:intsearch(vector<int>&nums,inttarget){if(nums.size()==0){return-1;}intpos=findPos(nums,0,nums.size()-1);if(pos==-1){returnfindVal(nums,0,nums.size()-1,target);}if(targ...
Search in Rotated Sorted Array Deion: Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise...