Write a function to determine if a given target is in the array. 题解: 这道题与之前Search in Rotated Sorted Array类似,问题只在于存在dupilcate。那么和之前那道题的解法区别就是,不能通过比较A[mid]和边缘值来确定哪边是有序的,会出现A[mid]与边缘值相等的状态。所以,解决方法就是对于A[mid]==A...
1. http://bangbingsyb.blogspot.com/2014/11/leetcode-search-in-rotated-sorted-array.html 2. http://www.programcreek.com/2014/06/leetcode-search-in-rotated-sorted-array-java/
Search in Rotated Sorted Array I Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You may ...
publicintsearch(int[]nums,inttarget){intstart=0;intend=nums.length-1;//找出最小值的数组下标/* while (start < end) {int mid = (start + end) / 2;if (nums[mid] > nums[end]) {start = mid + 1 ;} else {end = mid;}}int bias = start;*///找出最大值的数组下标while(start<end...
81. Search in Rotated Sorted Array II https://leetcode.com/problems/search-in-rotated-sorted-array-ii/ 这两道题都是属于循环有序数组的查找问题,无论是查找具体元素的下标还是检查一个目标值是否在数组中,主要的判断逻辑都是一致的。
There is an integer arraynumssorted in ascending order (with distinct values). Prior to being passed to your function,numsis rotated at an unknown pivot indexk(0 <= k < nums.length) such that the resulting array is[nums[k], nums[k+1], ..., nums[n-1], nums[0], nums[1], ....
Runtime: 0 ms, faster than 100.00% of Java online submissions for Search Insert Position. \classSolution{publicintsearch(int[]nums,inttarget){intn=nums.length;if(n==0)return-1;intleft=0;intright=n-1;while(left+1<right){intmid=left+(right-left)/2;if(nums[mid]==target){returnmid;...
33. Search in Rotated Sorted Array 寻找旋转排序数组 There is an integer array nums sorted in ascending order (with distinct values). 一个升序排序的整数数组 Prior to being passed to your function, nums is possibly rotated at an unknown pivot index k (1 <= k < nums.length) such that th...
Search in Rotated Sorted Array 描述 Suppose a sorted array is rotated at some pivot unknown to you beforehand. 2.1 数组 5 (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return ...
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