String userName = myObj.nextLine();// 读取用户输入System.out.println("UserName = "+ userName);// 输出用户的输入} } 2)使用 next() importjava.util.Scanner; publicclassMain{ publicstaticvoidmain(String[] args){ Scanner scanne
Scanner scanner = new Scanner(System.in); 接下来我们演示一个最简单的字符串输入,并通过 Scanner 类的 next() 与 nextLine() 方法获取输入的字符串: //创建Scanner对象 Scanner scanner = new Scanner(System.in); System.out.print("使用next()方法接收用户的输入:"); String str = scanner.next(); Sy...
Scanner input=new Scanner(System.in); System.out.println("输入一个带有空格的串用nextLine()输入"); String str1=input.nextLine(); System.out.println(str1); System.out.println("输入一个带有空格的串用next()输入"); String str2=input.next(); System.out.println(str2); System.out.println("...
import java.util.Scanner; public class Test1 { public static void main(String[] args) { //创建Scanner类型的对象(注意,要导包) //System.in:标准的输入流,默认指向键盘 Scanner sc1 = new Scanner(System.in); //接受整数 System.out.println("请输入一个整数"); //为了解决(避免)InputMismatchExcept...
import java.util.Scanner;/ (1)利用键盘录入，输入一个字符串 (2)统计该字符串中各个字符的数量 / public class InputString { public static void main(String[] args) { //获取键盘输入的字符串 Scanner sc=new Scanner(System.in);System.out.println("请输入一个字符串！");String st=sc....
Scanner、String(java基础知识十二) 1.Scanner的概述和方法介绍 * A:Scanner的概述 * 是一个从键盘输入的类,有final修饰,不能被子类继承 * Scanner sc = new Scanner(System.in); * String str = sc.nextLine(); * B:Scanner的构造方法原理 * Scanner(InputStream source)...
publicclassText{publicstaticvoidmain(String[]args){Scanner input=newScanner(System.in);System.out.println("请输入一个字符串(中间能加空格或符号)");String a=input.nextLine();System.out.println("请输入一个字符串(中间不能加空格或符号)");String b=input.next();System.out.println("请输入一个整...
import java.util.Scanner; public class ScannerUserInput { public static void main(String[] args) { // String input with the Java Scanner System.out.println("How old are you?"); Scanner stringScanner = new Scanner(System.in); String age = stringScanner.next(); System.out.println(age +...
Both hasNext and next methods may block waiting for further input. Whether a hasNext method blocks has no connection to whether or not its associated next method will block. The findInLine(java.lang.String), findWithinHorizon(java.lang.String, int), and skip(java.util.regex.Pattern) methods...
import java.util.Scanner; class Main { public static void main(String[] args) { Scanner myObj = new Scanner(System.in); System.out.println("Enter name, age and salary:"); // String input String name = myObj.nextLine(); // Numerical input int age = myObj.nextInt(); double salary...