There are ways than one to take input from the user in Java, and the Scanner class is only of them. However, it is probably the most commonly used as well due it’s ease of use. Another common way is theSystem.i
Input String: Hello World Hello PS C:\Users\admin\Desktop\java_code\用户输入> Scanner 类的 nextLine 方法 在以上基础上修改代码: importjava.util.Scanner;classTest{publicstaticvoidmain(String[] args){ String s; Scanner userInput=newScanner(System.in); System.out.print("Input String: ");if(us...
java.util.Scanner 是Java5的新特征,主要功能是简化文本扫描,这个类最实用的地方表现在获取控制台输入。当通过 new Scanner(System.in) 创建一个Scanner,控制台会一直等待输入,直到敲回车键结束,把所输入的内容传给 Scanner,作为扫描对象。如果要获取输入的内容,则只需要调用 Scanner 的 nextLine() 方法即可。 Scann...
importjava.util.Scanner;publicclassInputExample{publicstaticvoidmain(String[]args){Scannerscanner=newScanner(System.in);System.out.print("请输入一个整数: ");intnumber=scanner.nextInt();System.out.println("您输入的整数是: "+number);System.out.print("请输入一个字符串: ");Stringtext=scanner.nex...
$ javacScannerDemo.java $ javaScannerDemonext方式接收:runoob com输入的数据为:runoob 可以看到 com 字符串并未输出,接下来我们看 nextLine。 使用nextLine 方法: ScannerDemo.java 文件代码: importjava.util.Scanner;publicclassScannerDemo{publicstaticvoidmain(String[]args){Scannerscan=newScanner(System.in);...
Scanner类的常用方法1 其实上图的意思就是,比如:nextlnt():只读取int值,就是只能读取整数类型的数据,如果输入了非整型的数据(浮点型字符串等)就会报错。nextFloat()、nextDouble()这些也是以此类推,只能读取符合该类型的数据。 此处重点讲一下next()和nextLine()的区别 ...
Scanner input=new Scanner(System.in); System.out.println("输入一个带有空格的串用nextLine()输入"); String str1=input.nextLine(); System.out.println(str1); System.out.println("输入一个带有空格的串用next()输入"); String str2=input.next(); ...
boolean inputBoolean=scanner.nextBoolean(); 读取多个类型的输入(需要按照顺序调用相应的读取方法): 代码语言:javascript 代码运行次数:0 运行 AI代码解释 String name=scanner.next();int age=scanner.nextInt();scanner.nextLine();// 读取换行符,因为nextInt()之后会留下一个换行符在输入流中 ...
util.Scanner; class Main { public static void main(String[] args) { Scanner myObj = new Scanner(System.in); System.out.println("Enter name, age and salary:"); // String input String name = myObj.nextLine(); // Numerical input int age = myObj.nextInt(); double salary = myObj....
When a scanner throws an InputMismatchException, the scanner will not pass the token that caused the exception, so that it may be retrieved or skipped via some other method. Depending upon the type of delimiting pattern, empty tokens may be returned. For example, the pattern "\\s+" will...