Given a list, rotate the list to the right bykplaces, wherekis non-negative. For example: Given1->2->3->4->5->NULLandk=2, return4->5->1->2->3->NULL. 前边做过一个数组的翻转。数组的翻转用一个示例解释: k=K%len(num) num=[1,2,3,4,5],k=2 第一步,翻转 num=[5,4,3,2...
=null,停止。 (3)k的值可能大于链表总长度,需要对k取余,k = k%count; (4)使fast.next等于head,slow的下一个结点作为新的头结点。 packagemedium;importdataStructure.ListNode;publicclassL61RotateList {/** Given a list, rotate the list to the right by k places, where k is * non-negative. *...
由于一开始看错题目,以为rotate的部分要逆置。所以这里还是post出逆置的code。 AI检测代码解析 # Definition for singly-linked list. # class ListNode(object): # def __init__(self, x): # self.val = x # self.next = None class Solution(object): def reverse(self, head): org_head = head cur...
leetcode Rotate List 1. 题目描述 Given a list, rotate the list to the right bykplaces, wherekis non-negative. For example: Given 1->2->3->4->5->NULL andk= 2, return 4->5->1->2->3->NULL. 2.解决方案1 classSolution{ pu...
来自专栏 · LeetCode Description Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]). Find the minimum element. You may assume no duplicate exists in the array. Example 1: Input...
Output:[2,0,1] Constraints: The number of nodes in the list is in the range[0, 500]. -100 <= Node.val <= 100 0 <= k <= 2 * 10<sup>9</sup> 哈哈哈哈哈哈哈 这个题目是我刷LeetCode 有史以来解决的最快的一道题目! 题目名称叫旋转链表,其实只是将尾部的结点不断的追加到链表的头部上...
https://leetcode.com/explore/interview/card/top-interview-questions-easy/92/array/646/leetcode.com/explore/interview/card/top-interview-questions-easy/92/array/646/ Solutions: Given an array, rotate the array to the right byksteps, wherekis non-negative. ...
题目链接[https://leetcode-cn.com/problems/rotate-list/]tag: Medium Linked question: Given ...
题目链接:https://leetcode.com/problems/rotate-list/ 这个题目思路比较简单,但是处理一些corner cases要注意。长度为n的链表旋转n次得到的链表与原来相同。所以k次操作要取链表的长度的余数得到有效操作数m,相当于将后m个节点整体插入到头部变成前m个节点,注意链表的断裂操作使用的是先后指针法。代码如下; ...lee...
[LeetCode] Rotate List Rotate List Given a list, rotate the list to the right by k places, where k is non-negative. For example: Given 1->2->3->4->5->NULL and k = 2, return 4->5->1->2->3->NULL. Time Complexity 计算LinkedList长度: O(N)...