给定一个数组(array),将数组向右旋转k步(k>=0)。 不需要输出,只改变原来的数组就可以。 Solution 1: 每次循环将数组的元素都向后移动一位,循环k次。 classSolution:defrotate(self, nums: List[int], k: int) ->None:foriinrange(k): previous= nums[-1]forjinrange(len(nums)): nums[j], previou...
voidrotate(vector<int>& nums,intk) {intn =nums.size();if(n ==0|| k ==0)return;//求最大公约数inta = n, c = k, b = a %c;while(b !=0) { a=c; c=b; b= a %c; }//依次替换while(c--) {intoldNum =nums[c];intcurPos = (c + k) %n;while(curPos !=c) {intcu...
题目链接: Rotate Array : leetcode.com/problems/r 轮转数组: leetcode-cn.com/problem LeetCode 日更第 86 天,感谢阅读至此的你 欢迎点赞、收藏鼓励支持小满 发布于 2022-04-14 09:29 力扣(LeetCode) Python 算法 赞同添加评论 分享喜欢收藏申请转载 ...
Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. Note: Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem. ...
81. Search in Rotated Sorted Array II There is an integer arraynumssorted in non-decreasing order (not necessarily withdistinctvalues). Before being passed to your function,numsisrotatedat an unknown pivot indexk(0 <= k < nums.length) such that the resulting array is[nums[k], nums[k+1...
LeetCode之Rotate Array 1、题目 Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array[1,2,3,4,5,6,7]is rotated to[5,6,7,1,2,3,4]. Note: Try to come up as many solutions as you can, there are at least 3 different ...
Given an array nums, return true if the array was originally sorted in non-decreasing order, then rotated some number of positions (including zero). Otherwise, return false. There may be duplicates in the original array. Note: An array A rotated by x positions results in an array B of ...
来自专栏 · LeetCode Description Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]). Find the minimum element. You may assume no duplicate exists in the array. Example 1: Input...
class Solution { public void rotate(int[] nums, int k) { int len = nums.length; k = k % len; int count = 0; // 记录交换位置的次数,n个同学一共需要换n次 for(int start = 0; count < len; start++) { int cur = start; // 从0位置开始换位子 int pre = nums[cur]; do{ int...
154. 寻找旋转排序数组中的最小值 II - 已知一个长度为 n 的数组,预先按照升序排列,经由 1 到 n 次 旋转 后,得到输入数组。例如,原数组 nums = [0,1,4,4,5,6,7] 在变化后可能得到: * 若旋转 4 次,则可以得到 [4,5,6,7,0,1,4] * 若旋转 7 次,则可以得到 [0,1,4,4,5,