public void rotate(int[] nums, int k) { if (k > nums.length) { k = k % nums.length; } int tmp[] = (int[]) nums.clone(); for (int i = 0; i < k; i++) { nums[i] = tmp[tmp.length - k + i]; } for (int i = 0; i < (tmp.length - k); i++) { nums[k...
Rotate an array ofnelements to the right byksteps. For example, withn= 7 andk= 3, the array[1,2,3,4,5,6,7]is rotated to[5,6,7,1,2,3,4]. Hint: Could you do it in-place with O(1) extra space? link:https://leetcode.com/explore/interview/card/top-interview-questions-easy...
Rotate Array - LeetCode Rotate an array ofnelements to the right byksteps. For example, withn= 7 andk= 3, the array[1,2,3,4,5,6,7]is rotated to[5,6,7,1,2,3,4]. Note: Try to come up as many solutions as you can, there are at least 3 different ways to solve this pro...
Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. Note: Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem. ...
题目链接: Rotate Array : leetcode.com/problems/r 轮转数组: leetcode-cn.com/problem LeetCode 日更第 86 天,感谢阅读至此的你 欢迎点赞、收藏鼓励支持小满 发布于 2022-04-14 09:29 力扣(LeetCode) Python 算法 赞同添加评论 分享喜欢收藏申请转载 ...
LeetCode 189: Rotate Array (Java) 题目: Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. 两种解法: 第一种是原地swap,记录下被挤掉的数再接着swap,需要一些时间举栗子...
leetCode 33. Search in Rotated Sorted Array(c语言版本) bingo酱 I am a fighter 来自专栏 · leetcode每日斩 题目大意: 给定一个旋转升序的数组,所谓旋转就是假设把头和尾连接起来,然后找到最小那个数开始,往后开始就是升序的,直到再回到最小那个数为止。这样看起来就像一个环一样。 然后,现在给定一个数,...
class Solution { public void rotate(int[] nums, int k) { int len = nums.length; k = k % len; int count = 0; // 记录交换位置的次数,n个同学一共需要换n次 for(int start = 0; count < len; start++) { int cur = start; // 从0位置开始换位子 int pre = nums[cur]; do{ int...
Given an array, rotate the array to the right by k steps, where k is non-negative. Example 1: Input:[1,2,3,4,5,6,7]and k=3Output:[5,6,7,1,2,3,4]Explanation:rotate1steps to theright:[7,1,2,3,4,5,6]rotate2steps to theright:[6,7,1,2,3,4,5]rotate3steps to theri...
33. 搜索旋转排序数组 - 整数数组 nums 按升序排列,数组中的值 互不相同 。 在传递给函数之前,nums 在预先未知的某个下标 k(0 <= k < nums.length)上进行了 旋转,使数组变为 [nums[k], nums[k+1], ..., nums[n-1], nums[0], nums[1], ..., nums[k-1]](下标 从 0 开始