public class RotateArray { //审题不仔细: k是从右边开始的 public void rotate(int[] nums, int k) { /*int n = nums.length; //自己的space:O(n) if(n==1 || k>=n) return ; int[] replace = new int[n]; for(int i=0;i < n-1-k;n++){ replace[i] = nums[k+i]; } for(...
Rotate an array ofnelements to the right byksteps. For example, withn= 7 andk= 3, the array[1,2,3,4,5,6,7]is rotated to[5,6,7,1,2,3,4]. Note: Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem. https://leetcode....
andk=3,thearray[1,2,3,4,5,6,7] is rotatedto[5,6,7,1,2,3,4]. 思路分析: 这道题还是很常见的吧,只需要旋转三次就行了。但是,这道...问题描述:Rotateanarrayof n elementstotherightbyksteps. Note: Trytocome up as many solutions ...
Rotate an array of n elements to the right by k steps for example with n=7 and k=3,the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4] Try to come up as many solutions as you can,there are a...Rotate Array 问题描述: 对数组进行旋转,举个例子k = 3, the arr...
LeetCode笔记:189. Rotate Array 大意: 旋转一个有n个元素的数组,右移k步。 比如,n = 7,k = 3,数组 [1,2,3,4,5,6,7] 就被旋转为 [5,6,7,1,2,3,4]。 思路: 旋转本身没太多特别好说的,我的做法是用另一个数组来记录旋转后的内容,然后复制回原数组。当然记录时是从第nums.length-k个元素...
Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. Note: Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem. ...
题目: Rotate an array ofn elements to the right byk steps. For example, withn = 7 andk = 3, the array[1,2,3,4,5,6,7] is rotated to[5,6,7,1,2,3,4]. 将n个元素的数组按k级旋转。例如,n = 7和k = 3,数组[1,2,3,4,5,6,7]被旋转 dynamic-programming-python-leetcode(动...
189.Rotate Array Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. 解题思路: 使用数组自带的pop()方法和unshift()方法把数组最后一个取出来加入到头部。
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[Leetcode]-Rotate Array Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. 将固定数组循环右移k步 注意:当k>numsSize的时候k = k % numsSize......