List L,Rear,RL;intx; Rear=L=CreatList();for(inti=0;i<5;i++){scanf("%d",&x);Attach(L, x,&Rear); }PrintList(L);printf("\n"); RL=Reverse(L,4);PrintList(RL);return0; }
the reverse of the second element on followed by the first element. public ListNode Reverse(ListNode list) { if (list == null) return null; // first question if (list.next == null) return list; // second question // third question - in Lisp this is easy, but we don't have cons ...
02-线性结构3 Reversing Linked List(25 分) Given a constant K and a singly linked list L, you are supposed to reverse the links of every K elements on L. For example, given L being 1→2→3→4→5→6, if K=3, then you must output 3→2→1→6→5→4; if K=4, you must outpu...
import java.util.function.Function; public class Main { interface List<T> extends Function<Boolean, Object>{ default T head() { return (T)apply(true); } default List<T> tail() { return (List<T>)apply(false); } default T nth(int idx) { return idx == 0 ? head() : tail() =...
Linked List Cycle 题目链接 python代码实现: 实现思路: 快慢指针法。定义两个指针:快指针每次走一步;慢指针每次走两步。依次循环下去,如果链表存在环,那么快慢指针一定会有相等的时候。 为了便于理解,你可以想象在操场跑步的两个人,一个快一个慢,那么他们一定会相遇(无论他们的起始点是不是在操场)... ...
import java.util.function.Function; public class Main { interface List<T> extends Function<Boolean, Object>{ default T head() { return (T)apply(true); } default List<T> tail() { return (List<T>)apply(false); } default T nth(int idx) { return idx == 0 ? head() : tail() =...
Reverse Linked List 1,题目要求 Reverse a singly linked list. 翻转一个单链表。 2,题目思路 对于这道题,是单链表问题的一个非常经典的问题。一般来说,这个问题有两种解决办法:迭代与递归。 迭代: 迭代的方法相对来说比较简单。 我们首先定义一个节点,作为开始节点(NULL),然后在循环的过程中: 记录当前节点的...