当然代码还可以化简。 /*** Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * }*/publicclassSolution {publicListNode reverseBetween(ListNode head,
ListNode first=head; ListNode reverseHead=null;//建立一个新的节点用来存放结果while(first !=null) {//遍历输入链表,开始处理每一个节点ListNode second = first.next;//先处理第一个节点first,所以需要一个指针来存储first的后继first.next = reverseHead;//将first放到新链表头节点的头部reverseHead = first...
Reverse Linked List II Reverse a linked list from position m to n. Do it in-place and in one-pass. For example: Given 1->2->3->4->5->NULL, m = 2 and n = 4, return1->4->3->2->5->NULL. Note: Given m, n satisfy the following condition: 1 ≤ m ≤ n ≤ length of ...
publicclassSolution{publicListNodeReverseList(ListNode head){if(head==null)returnnull;//head为当前节点,如果当前节点为空的话,那就什么也不做,直接返回null;ListNode pre=null;ListNode nextnode=null;while(head!=null){nextnode=head.next;head.next=pre;pre=head;head=nextnode;}returnpre;}} Reverse Lin...
def reverseList(self, head): """ :type head: ListNode :rtype: ListNode """ dummy = ListNode(None) while head: # 终止条件是head=Null nextnode = head.next # nextnode是head后面的节点 head.next = dummy # dummy.next是Null,所以这样head.next就成为了Null ...
Reverse a singly linked list. click to show more hints. Hint: A linked list can be reversed either iteratively or recursively. Could you implement both? 既然问了能否iteratively or recursively, 那就both把. iterative 解法: 总结就是得到下一个节点,更改当前节点指向,将指针往下移动,直到过完整个linked...
java集合中:set与list相互转换[通俗易懂] 运行次数: Set<String>set=newHashSet<String>();set.add("c");set.add("d");set.add("a");set.add("a");//方法一:List<String>list=newArrayList<String>(set);for(Strings:list){System.out.println(s);}System.out.println();//方法二:List<String>...
LeetCode Top 100 Liked Questions 25. Reverse Nodes in k-Group (Java版; Hard) 题目描述 Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. k is a positive integer and is less than or equal to the length of the linked list. If the nu...
javaCopy code // 伪代码，展示垃圾回收的基本概念 public class GarbageCollectionExample { public ...
249 Reverse Integer.java Easy Java [Math] 250 Swap Nodes in Pairs.java Medium Java [Linked List] 251 Find Peak Element II.java Hard Java [Binary Search, DFS, Divide and Conquer] 252 Sqrt(x).java Easy Java [Binary Search, Math] 253 First Bad Version.java Easy Java [Binary Search...