LeetCode 206. Reverse Linked List(C++) 题目: Reverse a singly linked list. Example: Input: 1->2->3->4->5->NULL Output: 5->4->3->2->1->NULL Follow up: A linked list can be reversed either iteratively or recursively. Could you implement both? 分析: 分别用迭代和递归来实现。 迭代...
做II之前应该先来做1的,这个倒是很简单,基本上不用考虑什么,简单的链表反转而已: 1/**2* Definition for singly-linked list.3* struct ListNode {4* int val;5* ListNode *next;6* ListNode(int x) : val(x), next(NULL) {}7* };8*/9classSolution {10public:11ListNode* reverseList(ListNode*h...
https://leetcode-cn.com/problems/reverse-linked-list/solution/shi-pin-jiang-jie-die-dai-he-di-gui-hen-hswxy/ python # 反转单链表 迭代或递归 class ListNode: def __init__(self, val): self.val = val self.head = None class Solution: def reverseList2(self, head: ListNode) -> ListNode...
[LeetCode]Reverse Linked List Question Reverse a singly linked list. 本题难度Easy。 3指针法 复杂度 时间O(N) 空间 O(1) 思路 利用3个指针对链表实施reverse。 代码 /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val ...
LeetCode 206. 反转链表(Reverse Linked List) 示例: 输入:1->2->3->4->5->NULL输出:5->4->3->2->1->NULL 切题 一、Clarification 只需注意为空链表的情况 二、Possible Solution 1、迭代 2、递归 可利用哨兵简化实现难度 Python3 实现
https://leetcode.com/problems/reverse-linked-list/discuss/140916/Python-Iterative-and-Recursive recursive method 每次把head.next保存下来,这样就不用像我之前写的那样,用while循环去找最后一个node了,大大降低了时间复杂度 直接将linked list的值存入stack就好,不需要把整个node存进去。只存值的好处是后面可以...
Leetcode 92题反转链表 II(Reverse Linked List II) 题目链接 https://leetcode-cn.com/problems/reverse-linked-list-ii/ 题目描述 反转从位置 m 到 n 的链表。请使用一趟扫描完成反转。 说明: 1 ≤ m ≤ n ≤ 链表长度。 示例: 输入: 1->2->3->4->5->NULL, m = 2, n = 4 输出: 1->4...
A set of practice note, solution, complexity analysis and test bench to leetcode problem set - leetcode/add Reverse Linked List II.drawio at b58bcceb0ea27d0756ad72fb6a64b3b547fae221 · brianchiang-tw/leetcode
package leetcode import "strings" func reverseWords151(s string) string { ss := strings.Fields(s) reverse151(&ss, 0, len(ss)-1) return strings.Join(ss, " ") } func reverse151(m *[]string, i int, j int) { for i <= j { (*m)[i], (*m)[j] = (*m)[j], (*m)[i]...
Can you solve this real interview question? Reverse Linked List - Given the head of a singly linked list, reverse the list, and return the reversed list. Example 1: [https://assets.leetcode.com/uploads/2021/02/19/rev1ex1.jpg] Input: head = [1,2,3,