leetcode 206. Reverse Linked List 反转字符串 Reverse a singly linked list. 反转链表,我这里是采用头插法来实现反转链表。 代码如下: /*class ListNode { int val; ListNode next; ListNode(int x) { val = x; } } */ public class Solution { public ListNode reverseList(ListNode head) { if(head...
A linked list can be reversed either iteratively or recursively. Could you implement both? 解法一:(C++) 利用迭代的方法依次将链表元素放在新链表的最前端实现链表的倒置 1classSolution {2public:3ListNode* reverseList(ListNode*head) {4ListNode* newhead=NULL;5while(head){6ListNode* t=head->next;7h...
//reverse-linked-list.cpp /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ //basic reverse //Time:O(n), Space:O(1) classSolution{ ...
题目链接:https://leetcode.com/problems/reverse-linked-list/ 方法一:迭代反转 https://blog.csdn.net/qq_17550379/article/details/80647926讲的很清楚 方法二:递归反转 解决递归问题从最简单的c
反转链表(Reverse Linked List)C++递归实现 /** * @author:leacoder * @des: 递归实现 反转链表 */class Solution{public:ListNode*reverseList(ListNode*head){//第一个条件是判断递归开始,传入的参数的合法性。第二个是递归的终止条件if(NULL==head||NULL==head->next)returnhead;ListNode*result=reverseList...
Reverse Linked List II 题目大意 翻转指定位置的链表 解题思路 将中间的执行翻转,再将前后接上 代码 迭代 代码语言:javascript 复制 classSolution(object):# 迭代 defreverseBetween(self,head,m,n):""":type head:ListNode:type m:int:type n:int:rtype:ListNode""" ...
Consequently, the main program calls the printNodes function for the user to compare modified linked list contents. #include <iostream> #include <string> #include <vector> using std::cin; using std::cout; using std::endl; using std::string; using std::vector; struct Node { struct Node ...
206. Reverse Linked List Reverse a singly linked list. 反转一个链表。 思路: 采用头插法,将原来链表重新插一次返回即可。 代码如下: /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} ...
#@author:leacoder#@des: 迭代 + 哨兵 反转链表 II# Definition for singly-linked list.# class ListNode:# def __init__(self, x):# self.val = x# self.next = NoneclassSolution:defreverseBetween(self,head:ListNode,m:int,n:int)->ListNode:ifm==n:returnhead ...
Breadcrumbs Programming-In-C /Linked List / Reverse_doubly_linked_list.cppTop File metadata and controls Code Blame 101 lines (90 loc) · 1.71 KB Raw #include<bits/stdc++.h> using namespace std; class node { public: int data; node* next; node* prev; node(int value) { data = valu...