思路:从左到右遍历S中的字符,定义两个变量left和right,记录遇到的左括号、右括号的数量,当左括号和右括号的数量相等时,说明遇到了一个原始有效字符串,去掉头尾的括号,借助字符串截取完成,拼接到StringBuilder中。 publicStringremoveOuterParentheses(String S){StringBuildersb=newStringBuilder();intleft=0, right =0...
classSolution:defremoveOuterParentheses(self, S: str) ->str: size=len(S)ifsize==0:return""i=0 strings=[]whilei<size: stack=[S[i]] string=S[i] i+=1whilei<size:ifS[i]=='(': stack.append(S[i])else: stack.pop() string+=S[i] i+=1ifnotstack:breakstrings.append(string) str...
A valid parentheses string S is primitive if it is nonempty, and there does not exist a way to split it into S = A+B, with A and B nonempty valid parentheses strings. Given a valid parentheses string S, consider its primitive decomposition: , where Return S after removing the outermost ...
+ P_k, where P_i are primitive valid parentheses strings. Return S after removing the outermost parentheses of every primitive string in the primitive decomposition of S. Example 1: Input: "(()())(())" Output: "()()()" Explanation: The input string is "(()())(())", with ...
宗策 0 925 LeetCode 1021. Remove Outermost Parentheses 2019-12-22 08:20 − 原题链接在这里:https://leetcode.com/problems/remove-outermost-parentheses/ 题目: A valid parentheses string is either empty (""), "(" + A + ")", or&n... Dylan_Java_NYC 0 432 < 1 > 2004...
Remove Outermost Parentheses 2019-12-22 08:20 − 原题链接在这里:https://leetcode.com/problems/remove-outermost-parentheses/ 题目: A valid parentheses string is either empty (""), "(" + A + ")", or&nb... Dylan_Java_NYC 0 432 C++:基本类型的转换 2019-12-06 17:32 − # ...
今天介绍的是LeetCode算法题中Easy级别的第242题(顺位题号是1021)。有效的括号字符串为空(""),"("+ A +")"或A + B,其中A和B是有效的括号字符串,+表示字符串连接。例如,"","()","(())()"和"(()(()))"都是有效的括号字符串。 如果有效的括号字符串S是非空的,并且不存在将其拆分为S = A...
LeetCode 中关于括号的题目还是比较多的,比如 Valid Parentheses,Valid Parenthesis String,Remove Invalid Parentheses,和 Longest Valid Parentheses 等。大多都是考察如何判断一个括号字符串是否合法,所谓的合法,大致就是左右括号个数要相同,每个右括号前面必须要有对应的左括号,一个比较简单的判断方法就是用一个变量 ...
ReturnSafter removing the outermost parentheses of every primitive string in the primitive decomposition ofS. Example 1: Input:"(()())(())" Output:"()()()" Explanation: The input string is "(()())(())", with primitive decomposition "(()())" + "(())". ...
Sis a valid parentheses string 解题思路:括号配对的题目在leetcode出现了很多次了,从左往右遍历数组,分别记录左括号和右括号出现的次数,当两者相等的时候,即为一组括号。 代码如下: classSolution(object):defremoveOuterParentheses(self, S):""":type S: str ...