LeetCode-Remove Invalid Parentheses Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other than the parentheses ( and ). Example1: Input:"()())()"Output: ["()()()", "(())...
So, when we delete one ')' for '())' and move forward, we should record the one we deleted (saying lastRemoved), and if we need delete more in the following, we should start our consideration from lastRemoved+1. Solution: publicclassSolution {publicList<String>removeInvalidParentheses(Str...
Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other than the parentheses ( and ). Example 1: Input: "()())()" Output: ["()()()", "(())()"] Example 2: Input: "...
301. Remove Invalid Parentheses 样例 Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other than the parentheses ( and ). Example 1: Input: "()())()" Output: ["()()()", ...
【Leetcode】Remove Invalid Parentheses 题目链接:https://leetcode.com/problems/remove-invalid-parentheses/ 题目: Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other than the ...
简介:删除最小数量的无效括号,使得输入的字符串有效,返回所有可能的结果。说明: 输入可能包含了除 ( 和 ) 以外的字符。 Description Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. ...
classSolution{ intl,r,max,maxLen;// 分别记录左括号数目、右括号数目、最多可以匹配的括号对数、最长子串长度 Set<String>ans=newHashSet<>(); publicList<String>removeInvalidParentheses(Strings) { for(inti=0;i<s.length();i++) { if(s.charAt(i)=='(')l++; ...
Can you solve this real interview question? Minimum Remove to Make Valid Parentheses - Given a string s of '(' , ')' and lowercase English characters. Your task is to remove the minimum number of parentheses ( '(' or ')', in any positions ) so that the
class Solution{public:vector<string>removeInvalidParentheses(string s){queue<pair<string,int>>q;q.push(make_pair(s,0));vector<string>result;while(!q.empty()){autop=q.front();q.pop();string ss=p.first;if(is_valid(ss))result.push_back(ss);elseif(result.empty())for(inti=p.second;...
Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. 1 当有连续的右括号的时候,我们一般删除第一个 2 定义一个子函数,用于判断一个string是否是valid,首先用一个计数变量,遇到‘(’加1,遇到‘0’减1,在减一的时候,判断这个计数变量是否...