class Solution: # 定义一个方法,用于移除单向链表中的倒数第n个节点 def removeNthFromEnd(self, head, n): # 定义一个递归函数,用于实际执行移除操作 def remove(head): # 如果当前节点为空,则返回0和空节点。这表示已经到达链表末尾。 if not head: return 0, head # 递归
}// 删除第n个节点// ListNode nthNode = p1.next;p1.next = p1.next.next;// nthNode.next = null;returndummy.next; } }// Runtime: 6 ms// Your runtime beats 100.00 % of java submissions. Python 实现 # Definition for singly-linked list.# class ListNode:# def __init__(self, x...
After removing the second node from the end, the linked list becomes 1->2->3->5. Note: Givennwill always be valid. Try to do this in one pass. Show Tags SOLUTION 1: 1.使用快慢指针,快指针先行移动N步。用慢指针指向要移除的Node的前一个Node. 2. 使用dummy node作为head的前缀节点,这样...
每日算法之十八: Remove Nth Node From End of List Given a linked list, remove the nthnode from the end of list and return its head. For example, Given linkedlist:1->2->3->4->5,andn=2.After removing the second node from the end,the linkedlistbecomes1->2->3->5. 1. 2. 3. Not...
class Solution { public: ListNode* removeNthFromEnd(ListNode* head, int n) { ListNode *dummy = new ListNode(-1); dummy->next = head; ListNode *p = dummy, *q = dummy; for(int i=0; i<n; i++) q = q->next; while(q->next) ...
Remove Nth Node From End of List 2. Solution Version 1 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */class Solution{public:ListNode*removeNthFromEnd(ListNode*head,intn){if(!head||...
19. Remove Nth Node From End of List Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. ...
28. Nth Node Removal Variants Write a C program to remove the Nthnode from the end of a singly linked list. Sample Solution: C Code: #include<stdio.h>#include<stdlib.h>// Structure for defining a Node in a Singly Linked ListstructNode{intdata;// Data stored in the nodestructNode*nex...
Given the head of a linked list, remove the nth node from the end of the list and return its head.impl Solution { pub fn remove_nth_from_end(head: Option<Box<ListNode>>, n: i32) -> Option<Box<ListNode>> { let mut dummy = Some(B
*/publicclassSolution{publicListNoderemoveNthFromEnd(ListNode head,intn){if(head ==null)returnnull;if(head.next ==null)returnnull; ListNode p1, p2;intflag=1; p1 = p2 = head;for(inti=0; i < n; i++) {if(p2.next !=null)