题目: Write a function to delete a node (except the tail) in a singly linked list, given only access to that node. Supposed the linked list is1 -> 2 -> 3 ->...查看原文leetcode Remove Nth node from end of list C++ of list and return its head. Example: Given linked list: 1->...
019 删除链表的倒数第N个节点 每天一算:Remove Nth Node From End of List 020 有效的括号 每天一算:Valid Parentheses 024 两两交换链表中的节点 每天一算:Swap Nodes in Pairs 026 删除排序数组中的重复项 图解LeetCode第 26 号问题:删除排序数组中的重复项 075 颜色分类 每天一算:Sort Colors 086...
DeleteKthNode.java InsertAtHead.java InsertAtTail.java LL_basic.java LL_traversal.java Doubly_Linked_List Singly_Linked_List imgs detectandremove.java detectloop.java floydCycleDetection.java intersectionPoint.java intersectionPointEfficient.cpp merge_sorted_lists.cpp middle_el.java nthNodefromEnd.java...
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CurrentNode = *q.Delete(CurrentNode); } } 开发者ID:ChenBoTang,项目名称:fds,代码行数:12,代码来源:leviter.cpp 示例4: Run ▲点赞 1▼ voidAirport::Run(){intpri; airplane p;for(nowtime=1;nowtime<=endtime;nowtime++){cout<<"\nThe "<<nowtime<<" Minutes"; ...
要求 给定链表中的一个节点,删除该节点 思路 通过改变节点的值实现 实现 1 struct ListNode { 2 int val; 3 ListNode *next; 4 ListNode(int x) : val(x), next(NULL) {} 5 }; 6 7 class Solutio
因为本题没有给我们 head 结点,所以我们不可能得到要删除的结点 node 的前一个结点 pre,所以是不可能删除掉 node 结点本身的。 我们可以利用结点唯一这个条件,将要删除的结点 node 后面的结点 next 的值覆盖到 node 上面,然后删除掉 next 直接,就等价于删除掉 node 结点。
代码语言:javascript 复制 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */classSolution{public:voiddeleteNode(ListNode*node){ListNode*pre;ListNode*current=node;while(current->next){pre=current...
Supposed the linked list is1 -> 2 -> 3 -> 4and you are given the third node with value3, the linked list should become1 -> 2 -> 4after calling your function. Subscribeto see which companies asked this question 解法:题目要求我们删除链表中的一个节点,但是并不告诉我们链表的头节点,而只...